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bulgar [2K]
3 years ago
14

The price of Pepsi stock was $0.65 in 1981 and $27.56 in 2011. What was the average rate of change for the stock per year

Mathematics
1 answer:
pychu [463]3 years ago
4 0
0.65 at year 0 (0, 0.65)
27.56 at year 30 (30, 27.56)

slope = (27.56 - 0.65) / (30 - 0)
slope = 26.91 / 30

Change = 0.897 or almost 90 cents
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The quality control manager of a soda manufacturing company wishes to use a significant level of 0.05 to test whether the variab
Alex17521 [72]

Answer: 1.645

Step-by-step explanation:

Given : The quality control manager of a soda manufacturing company wishes to use a significant level of 0.05 to test whether the variabilities in the amount of soda in the company's 16 OZ bottles is more than the variabilities in the company's 12 OZ bottles.

Let \sigma_1^2 represents the variance for 16 OZ bottles and \sigma_2^2 represents the variance for 12 OZ bottles.

The Null and Alternative Hypothesis will be  :-

H_0:\sigma_1^2\geq\sigma_2^2

H_1:\sigma_1^2, since alternative hypothesis is left-tailed , then the test is left-tailed test.

By using the standard normal distribution table for z, the critical value for this hypothesis:-

z_{\alpha}=z_{0.05}=1.645

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4 years ago
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Virty [35]
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Solve 6-2x=3<br><br><br><br><br><br><br> (bensjdkmenskkw)
Kamila [148]

Answer:

answer: 4.5

Step-by-step explanation:

2x=3+6

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Lou has an account with $10,000 which pays 6% interest compounded annually. If to that account, Lou deposits $5,000 at the begin
katovenus [111]

Answer:

Option d. $22154 is the right answer.

Step-by-step explanation:

To solve this question we will use the formula A=P(1+\frac{r}{n})^{nt}

In this formula A = amount after time t

                        P = principal amount

                        r = rate of interest

                       n = number of times interest gets compounded in a year

                        t = time

Now Lou has principal amount on the starting of first year = 10000+5000 = $15000

So for one year A=15000(1+\frac{\frac{6}{100}}{1})^{1\times1}

= 15000(1+.06)^{1}

= 15000(1.06) = $15900

After one year Lou added $5000 in this amount and we have to calculate the final amount he got

Now principal amount becomes $15900 + $ 5000 = $20900

Then putting the values again in the formula

A=20900(1+\frac{\frac{6}{100}}{1})^{1\times1}

= 20900(1+.06)^{1}

= 20900(1.06)=22154

So the final amount will be $22154.

3 0
3 years ago
What’s the correct answer ?
Leona [35]
The answer is a) 35


The steps:
180° - 95 ° = 85 °
180 ° - (85 ° + 60 °)=35 °
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