A Total of 6 Days!
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<u>Problem</u>
A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?
<u>Work </u>
Probability = no. of favorable outcomes /total no. of outcomes
Probability of getting a blue marble=5/5+6+9=5/20
Probability of getting a red marble=6/20−1=6/19
5/20×6/19
<u>Answer</u>
3/20
So it is C.
Since there are no multiples other than 1 and -1 that could multiply in any way to equal 1, those are the only numbers you can really work with
it is a possibility that a, b, and c could equal 1 but then it would go wrong when comes time to subtract since all numbers are equal and cannot subtract largest from smallest.
a logical approach would be to try -1, -1, and 1 since -1 * -1 = 1 and then 1* 1 =1
we can make a= -1 , b= -1, and c= 1
(we need b to equal -1 so that we get an answer of -1 opposed to if we made a=-1 and c=-1, all outcomes would equal 1)
-1²=1
-1³=-1
1⁴= 1
since 1 is the largest possible outcome and -1 is the lowest possible outcome you should subtract the two
1-(-1) = 1+1 = 2
The answer should be D: 2
hoped this helped at all!
Answer:
The correct ans is...
3 x square + 5 x - 5
Step-by-step explanation:
U can only subtract or add if u hv the same variable..
here -2x and 7x have the same variable...
so -2x + 7x = 5x
Therefore the ans is....
3 x square + 5 x - 5
Hope this helps....
Have a GOOD DAY !!!!
Pls mark my ans as brainliest
If u mark my ans as brainliest u will get 3 extra points
Sry to say....
U really need to read ur Math TBK
Answer:
57 degrees
Step-by-step explanation:
because it is the same as the other side