== You're pushing the load <u><em>straight</em></u> along the horizontal surface at a <u><em>constant speed</em></u>.
== The speed and direction of the load are not changing, so there is <u><em>no acceleration.</em></u>
== From Newton's 2nd law of motion, we know that F = m A . Since A=0, F must also be zero. That means <em>NO NET FORCE</em> is acting on the load.
== But how can that be ? You're pushing it with 90 N !
== The NET force is zero. So something else must be pushing the box, also with <em>90 N of force, exactly opposite to YOUR force, </em>and they add up to zero.
== THERE's your force of friction !
Answer:
The volume of the bubble near the surface will be 9.47 m³
Explanation:
Given that,
Depth = 52.0 m
Volume = 1.50 m³
Temperature at bottom = 5.5°C
Temperature at the top = 18.5°C
We need to calculate the pressure at the depth 52.0 m
The pressure is
Where, = Pressure at the surface
= Pressure at the depth
Put the value into the formula
We need to calculate the volume of the bubble just before it reaches the surface
Using equation of ideal gas
Now, The equation of at bottom and top
Put the value into the formula
Hence, The volume of the bubble near the surface will be 9.47 m³
The velocity of the package after it has fallen for 3.0 s is 29.4 m/s
From the question,
A small package is dropped from the Golden Gate Bridge.
This means the initial velocity of the package is 0 m/s.
We are to calculate the velocity of the package after it has fallen for 3.0 s.
From one of the equations of kinematics for objects falling freely,
We have that,
v = u + gt
Where
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
and t is time
To calculate the velocity of the package after it has fallen for 3.0 s
That means, we will determine the value of v, at time t = 3.0 s
The parameters are
u = 0 m/s
g = 9.8 m/s²
t = 3.0 s
Putting these values into the equation
v = u + gt
We get
v = 0 + (9.8×3.0)
v = 0 + 29.4
v = 29.4 m/s
Hence, the velocity of the package after it has fallen for 3.0 s is 29.4 m/s
Learn more here: brainly.com/question/13327816
I really wish I could help but I really dk the answer and I need points asappppp so that I can get answers to my questions so I can give them in rnnnn!!! Sorryyyyy (atleast I'm being honest)
Answer:
B) the aluminum
Explanation:
The density of an object is proportional to its mass and inversely proportional to its volume. Since lead is denser than aluminum and both pieces have the same mass, then the aluminum piece has a larger volume and due to this, it will also displace more fluid. The buoyant force is proportional to the volume of the displaced fluid. Therefore, the buoyant force on aluminum is greater.