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Grace [21]
3 years ago
8

A stone is dropped of a 1296-ft-cliff. The height of the stone above the ground is given by the equation h= - 16t^2+1296, where

h is the stone’s height in feet, and t is the time in seconds after the stone is dropped. Find the time required for the stone to hit the ground.
Mathematics
1 answer:
stich3 [128]3 years ago
3 0

When stone hits the ground, it's height will be zero, and since we're finding the time that's required for the stone to hit the ground, we can set h = 0 and solve for t.

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X^2-5x+2 x 3x^2 +2x +3
Katen [24]

Answer:

3x^4 - 13x^3 - x^2 - 11x + 6.

Step-by-step explanation:

x^2-5x+2 x 3x^2 +2x +3

= x^2(3x^2 +2x +3)  - 5x(3x^2 +2x +3) + 2(3x^2 +2x +3)

=  3x^4 + 2x^3 + 3x^2 - 15x^3 - 10x^2 - 15x + 6x^2 + 4x + 6

Adding like terms:

= 3x^4 - 13x^3 - x^2 - 11x + 6.

5 0
3 years ago
two riders rode a total of 165 miles. if they replaced each horse with a fresh horse every 11 miles, how many horses would they
shusha [124]

They would have used a total of 30 horses. Each person would've each ridden 15 so 15+15= 30 and 165 divided by 11 is 15. Hope this is off help!

3 0
4 years ago
How many learners can enrol if there are 12 teachers and a ratio of teachers to learners is 30:1
VladimirAG [237]

Answer:

360 learners

Step-by-step explanation:

One way to solve these types of problems is that you could set up a proportion

learners/teachers = learners/teachers

Let x = no. of learners to enrol

30/1 = x/12

12(30) = x

x = 360 learners

5 0
3 years ago
One equation in a system of equations is y= 3/4x -1. For which second equation would the system have exactly one solution? Choos
musickatia [10]

Answer:

2iiej

Step-by-step explanation:

1kejes191828wusnalao

3 0
3 years ago
If f(x) = x^4-x^3+x^2 and g(x)= -x^2, where x does not = 0, what is (f/g)(x)?
Korvikt [17]

For this case we have the following functions:

f (x) = x ^ 4-x ^ 3 x ^ 2\\g (x) = - x ^ 2

By definition of composition of functions we have to:(f \ g) (x) = \frac {f (x)} {g (x)}

So:

\frac {f (x)} {g (x)} = \frac {x ^ 4-x ^ 3 x ^ 2} {- x ^ 2} = \frac {x ^ 4} {- x ^ 2} +\frac {-x ^ 3} {- x ^ 2}+ \frac {x ^ 2} {- x ^ 2} =

By definition of division of powers of the same base we have to place the same base and subtract the exponents:

\frac {f (x)} {g (x)} = - x ^ 2+x-1

ANswer:

(\frac {f} {g}) (x) = - x ^ 2 +x-1

3 0
3 years ago
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