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2 years ago

What was the effect of decreasing the copper's mass?

Chemistry

2 answers:

MAXImum [283]2 years ago

5 0

Answer:

Decreasing the temperature of the copper made the final temperature decrease.

kondor19780726 [428]2 years ago

3 0

Answer:

Increasing the temperature of the copper made the final temperature increase and decreasing the temperature of the copper made the final temperature decrease. ... How does changing the initial mass of the copper affect how much heat energy it has? The more copper, the more heat energy.

Explanation:

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Please help! I really need help on this!

sineoko [7]

Answer:

I wanna say c

Explanation:

It makes the most sense, because non-metals don't produce an electrical current, and therefore aren't conductors.

5 0

2 years ago

Good evening! Does anyone know this? Earth Science

riadik2000 [5.3K]

The fraction of Earth's radius (6371 km) relative to the thickness of the oceanic (7.5 km) and continental crust (35 km) is 0.12 and 0.55, respectively.

What we know:

The average radius of Earth (E) = 6371 km

The average thickness of oceanic crust (O) = 7.5 km

The average thickness of continental crust (C) = 35 km

We need to convert all the above units from kilometers to miles:

$E = \frac{0.6214 mi}{1 km}*6371 km = 3958.9 mi$

$O = \frac{0.6214 mi}{1 km}*7.5 km = 4.7 mi$

$C = \frac{0.6214 mi}{1 km}*35 km = 21.7 mi$

Now, we can calculate the fraction of Earth's radius relative to each type of crust, with the given equation:

$X = \frac{avg. \: thickness}{avg. \: radius} \times 100$

<u>For the oceanic crust (O)</u>:

$X = \frac{4.7 mi}{3958.9 mi}\times 100 = 0.12$

<u>For the continental crust (C)</u>:

$X = \frac{21.7 mi}{3958.9 mi}\times 100 = 0.55$

Therefore, the fraction of Earth's radius relative to the oceanic and continental crust is 0.12 and 0.55, respectively.

You can see another example of calculation of fractions of Earth's radius here: brainly.com/question/4675868?referrer=searchResults

I hope it helps you!

6 0

2 years ago

Which sentence correctly explains the process and conditions needed for sleet to form?

laiz [17]

Answer:Sleet only happens under very specific weather conditions. There must be a layer of air near the ground whose temperature is below freezing, where water turns to ice. Above this layer of freezing air must be a layer of warmer air. As snow falls through the warm air, it melts or partially melts into raindrops.

Explanation:

3 0

2 years ago

What volume of a 0.33-M C12H22O11 solution can be diluted to prepare 25 mL of a solution with a concentration of 0.025 M?

Vsevolod [243]

The dilution formula can be used to find the volume needed

c1v1 = c2v2

Where c1 is concentration and v1 is volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

c1 - 0.33 M

c2 - 0.025 M

v2 - 25 mL

Substituting these values in the equation

0.33 M x v1 = 0.025 M x 25 mL

v1 = 1.89 mL

Therefore 1.89 mL of the 0.33 M solution needs to be diluted up to 25 mL to make a 0.025 M solution

7 0

3 years ago

IM ON A TIMER! What are the main types of star clusters? Check all that apply.

jekas [21]

There are globular and open star clusters, but there are no binary, eclipsing, or wobbling ones.

8 0

3 years ago

Read 2 more answers