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Fiesta28 [93]
1 year ago
6

a 4.4 g sample of gas occupies 2.24 l of volume at stp. without thinking too hard, what is the mw of the gas, and name two gases

that would have this mw. write out your logic.
Chemistry
1 answer:
garri49 [273]1 year ago
7 0

As a result, gas's molecular weight is 44g/mol. It is the gas's (Carbon dioxide) molecular weight.

What is Molecular Weight?

The total atomic weights of the atoms in a molecule are measured by its molecular weight. To calculate stoichiometry in chemical equations and reactions, chemists employ molecular weight. M.W. or MW are two frequent abbreviations for molecular weight. Atomic mass units (amu), Daltons, or a unitless expression can be used to indicate molecular weight (Da).

The mass of the isotope carbon-12, which is given a value of 12 amu, serves as the reference point for defining both atomic weight and molecular weight. Because there are many carbon isotopes, the atomic weight of carbon is not exactly 12.

A mole of any gas at STP takes up a volume of 22.4l

at STP, a gas fills a volume of 2.24l

Calculating the quantity of moles of gas in step two

Consequently, the amount of gas in moles

= 0.1 moles

This is equivalent to carbon dioxide's molecular weight.

=44g/mol

As a result, gas's molecular weight is 44g/mol. It is the gas's (Carbon dioxide) molecular weight.

Learn more about Molecular Weight from given link

brainly.com/question/837939

#SPJ4

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1. a. 3

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4 0
2 years ago
A sample of oxygen gas occupies a volume of 250 mL at .8 atm of pressure. What volume will it occupy at 1.2 atm of pressure?
musickatia [10]
167 mL

P1V1 = P2V2
P1 = .8 atm
V1 = 250 mL
P2 = 1.2 atm

Solve for V2 —> V2 = P1V1/P2

V2 = (0.8 atm)(250 mL) / (1.2 atm) = 167 mL
7 0
3 years ago
Which substance will most likely dissociate when it is dissolved in water?
Katyanochek1 [597]

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Which property controls the movement of groundwater by determining the rate at which water passes through the soil?
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Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid. HCl(aq), as described by
melisa1 [442]

Answer:

0.88 g

Explanation:

Using ideal gas equation to calculate the moles of chlorine gas produced as:-

PV=nRT

where,

P = pressure of the gas = 805 Torr

V = Volume of the gas = 235 mL = 0.235 L

T = Temperature of the gas = 25^oC=[25+273]K=298K

R = Gas constant = 62.3637\text{torr}mol^{-1}K^{-1}

n = number of moles of chlorine gas = ?

Putting values in above equation, we get:

805torr\times 0.235L=n\times 62.3637\text{ torrHg }mol^{-1}K^{-1}\times 298K\\\\n=\frac{805\times 0.235}{62.3637\times 298}=0.01017\ mol

According to the reaction:-

MnO_2+4HCl\rightarrow MnCl_2+2H_2O+Cl_2

1 mole of chlorine gas is produced when 1 mole of manganese dioxide undergoes reaction.

So,

0.01017 mole of chlorine gas is produced when 0.01017 mole of manganese dioxide undergoes reaction.

Moles of MnO_2 = 0.01017 moles

Molar mass of MnO_2 = 86.93685 g/mol

So,

Mass=Moles\times Molar\ mass

Applying values, we get that:-

Mass=0.01017moles \times 86.93685\ g/mol=0.88\ g

<u>0.88 g of MnO_2(s) should be added to excess HCl (aq) to obtain 235 mL of Cl_2(g) at 25 degrees C and 805 Torr.</u>

6 0
3 years ago
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