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2 years ago

5

You are taking hang-gliding lessons. The cost of the first lesson is one and a half times the cost of each additional lesson. Yo

u spend $260 for six lessons.

1 answer:

kow [346]2 years ago

8 0

So, givens: total lesson cost of $260, total lessons taken are 6, and the first lesson costs 1.5 (or 3/2) as much as the additional lessons.

First thing to do is to figure out how many additional lessons are in that, which are 5.

Then you can make a 1 variable equation with the information you have. I’m using x as my variable.

260= 3/2x + 5x

Combine like terms.

260 = 13/2x

Divide both sides by 13/2 (treat it as a fraction, and if your calculator cannot make fractions, then decimal might help for this. 13/2=6.5)

X=40

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X intercept is when y and z=0
yinter cept is when x and z =0
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set to zero and solve

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2 years ago

La expresion 18+2^3 / 4x2

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3 years ago

Plz help asap... Explain as much as possible to me plz

Solnce55 [7]

Answer:

see explanation

Step-by-step explanation:

Since the 2 figures are similar then the ratios of corresponding sides are equal, that is

$\frac{8}{x}$ = $\frac{18}{6}$ ( cross- multiply )

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x = $\frac{48}{18}$ = $\frac{8}{3}$ = 2 $\frac{2}{3}$

Similarly

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3 years ago

A man sold a fan for Rs. 400. Find the cost price if he incurred a loss of 15%.

statuscvo [17]

Answer:

Cost price of the fan is $\text {Rs. 470.59}$ .

Step-by-step explanation:

Given: A man sold a fan for $\text{Rs.}\:400$ . He incurred a loss of $15\%$ .

To find: The cost price of the fan

Solution:

We have,

Selling price, S.P., of the fan $= \text{Rs.} 400$

Loss $=15\%$

We know that $\text {Loss\%}=\frac{\text{C.P.-S.P.}}{\text{C.P.}}\times100\%$

Now let the C.P. of the fan be $\text{Rs.} \:x$

So, $15=(\frac{x-400}{x})\times 100$

$\implies 15x=100x-40000$

$\implies 100x-15x=40000$

$\implies 85x=40000$

$\implies x=\frac{40000}{85}$

$\implies x= 470.59$

Hence, the cost price of the fan is $\text {Rs. 470.59}$ .

7 0

2 years ago

A manufacturer wants to make open tin boxes from pieces of tin with dimensions 8 in. by 15 in. by cutting equal squares from the

Stells [14]

Answer:

$\frac{5}{3}$ in

Step-by-step explanation:

Let x be the side of square.

Length of box=8-2x

Width of box=15-2x

Height of box=x

Volume of box= $L\times B\times H$

Substitute the values then we get

Volume of box=V(x)= $(8-2x)(15-2x)x=(15x-2x^2)(8-2x)$

$V(x)=120x-30x^2-16x^2+4x^3$

$V(x)=4x^3-46x^2+120x$

Differentiate w.r.t x

$V'(x)=12x^2-92x+120$

$V'(x)=0$

$12x^2-92x+120=0$

$3x^2-23x+30=0$

$3x^2-18x-5x+30=0$

$3x(x-6)-5(x-6)=0$

$(x-6)(3x-5)=0$

$x-6=0\implies x=6$

$3x-5=0\implies x=\frac{5}{3}$

Again differentiate w.r.t x

$V''(x)=24x-92$

Substitute x=6

$V''(6)=24(6)-92=52>0$

Substitute x=5/3

$V''(5/3)=24(5/3)-92=-52$

Hence, the volume is maximum at x= $\frac{5}{3}$

Therefore, the side of the square , $x=\frac{5}{3}$ in cutout that gives the box the largest possible volume.

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2 years ago