All categories

3 years ago

What's 179 square root Show how

Mathematics

1 answer:

Jobisdone [24]3 years ago

5 0

Answer:

The square root of 179 rounded up to 7 decimal places is 13.3790882. It is the positive solution of the equation x² = 179.

You might be interested in

Determine the time necessary for P dollars to double when it is invested at interest rate r compounded annually, monthly, daily,

Rudik [331]

Answer:

Part 1) 8.17 years

Part 2) 4.98 years

Part 3) 4.95 years

Part 4) 4.95 years

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part 1) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% compounded annually

in this problem we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14\\n=1$

substitute in the formula above

$2p=p(1+\frac{0.14}{1})^{t}$

$2=(1.14)^{t}$

Apply log both sides

$log(2)=log[(1.14)^{t}]$

$log(2)=(t)log(1.14)$

$t=log(2)/log(1.14)$

$t=8.17\ years$

Part 2) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% compounded monthly

in this problem we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14\\n=12$

substitute in the formula above

$2p=p(1+\frac{0.14}{12})^{12t}$

$2=(\frac{12.14}{12})^{12t}$

Apply log both sides

$log(2)=log[(\frac{12.14}{12})^{12t}]$

$log(2)=(12t)log(\frac{12.14}{12})$

$t=log(2)/12log(\frac{12.14}{12})$

$t=4.98\ years$

Part 3) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% compounded daily

in this problem we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14\\n=365$

substitute in the formula above

$2p=p(1+\frac{0.14}{365})^{365t}$

$2=(\frac{365.14}{365})^{365t}$

Apply log both sides

$log(2)=log[(\frac{365.14}{365})^{365t}]$

$log(2)=(365t)log(\frac{365.14}{365})$

$t=log(2)/365log(\frac{365.14}{365})$

$t=4.95\ years$

Part 4) Determine the time necessary for P dollars to double when it is invested at interest rate r=14% continuously

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$t=?\ years\\ P=\$p\\A=\$2p\\r=14\%=14/100=0.14$

substitute in the formula above

$2p=p(e)^{0.14t}$

Simplify

$2=(e)^{0.14t}$

Apply ln both sides

$ln(2)=ln[(e)^{0.14t}]$

$ln(2)=(0.14t)ln(e)$

Remember that ln(e)=1

$ln(2)=(0.14t)$

$t=ln(2)/(0.14)$

$t=4.95\ years$

4 0

3 years ago

The local farm is advertising a special on fresh picked peaches. The farm charges $4.25 to pick

SOVA2 [1]

the cost to pick 3 pecks of peaches will be 14.75$

4 0

3 years ago

A company claims that their new bottle holds 25 % more laundry soap. If their original container held 53 fluid ounces of soap, h

LiRa [457]

53 * .25 = 13.25, 53 + 13.25 = 66.25 fluid ounces

4 0

3 years ago

Read 2 more answers

If m=(2x+1) and n=(6) and m+n=(9). Find x<br>

gregori [183]

Answer:

$\Large \boxed{x=1}$

Step-by-step explanation:

Substitute m=(2x+1) and n=(6) in m+n=(9).

We are finding the value of the x variable.

$2x+1+6=9$

Add the numbers on the left side of the equation.

$2x+7=9$

Subtract 7 from both sides.

$2x+7-7=9-7$

$2x=2$

Divide both sides by 2.

$\displaystyle \frac{2x}{2}=\frac{2}{2}$

$x=1$

The value of the x variable is 1.

7 0

3 years ago

Read 2 more answers

Jake and mike took a different number of tests. jake scored 85 points on each test. mike's total score was 15 less than jakes to

Daniel [21]

I am to believe that his score was 70.

since mike scored 15 less than 85 i had suspected it was 70

6 0

3 years ago