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Leokris [45]
3 years ago
9

The energy needed to remove an electron from an atom is called

Chemistry
1 answer:
Arlecino [84]3 years ago
3 0

Ionization energy, also called ionization potential, in chemistry, the amount of energy required to remove an electron from an isolated atom or molecule

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All of the following are examples of physical properties EXCEPT
stepladder [879]
Reaction with acid. That is a chemical reaction.
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3 years ago
When agno3 was added to test tube d it reacted with cl to form agcl precipitate. Did this result in a shift to the right or the
AlekseyPX

Answer:

Reaction will move rightwards.

Explanation:

Hello there!

In this case, according to the proposed question, it turns out possible for us to  figure out the effect of the addition of silver nitrate, by using the following representative equation for the formation of the silver chloride precipitate:

Ag^+(aq)+Cl^-(aq)\rightleftharpoons AgCl(s)

Now, due to the addition of silver nitrate, we will be actually adding silver ions to the solution, which means that, in terms of the Le Ch atelier's principle, the reaction will shift to the right towards the formation of more silver chloride precipitate.

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4 0
3 years ago
How many atoms are in 25.0 grams of carbon?
mars1129 [50]

mol = 25/12

= 2.083 mol

1 mol = 6.02 × 10^23 atoms

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X = 2.083/1 × 6.02 × 10^23

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5 0
3 years ago
The picture below shows an open field with wildflowers.
FromTheMoon [43]

Answer:

I think it's B

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8 0
3 years ago
Calorimetry can be used to find heats of combustion. suppose a calorimeter helps someone to determine that 4032 kj of heat is re
bezimeni [28]

Answer:

1008.0 kJ.

Explanation:

  • Firstly, we need to calculate the no. of moles of 88.0 g of propane:

<em>n = mass/molar mass </em>= (88.0 g)(/(44.0 g/mol) = <em>2.0 mol.</em>

∴ The combustion of 2.0 moles of propane produces 4032.0 kJ.

<em><u>Using cross multiplication: </u></em>

The combustion of 2.0 moles of propane produces → 4032.0 kJ.

The combustion of 0.5 moles of propane produces → ??? kJ.

<em>∴ The amount of heat released for the combustion of 0.5 moles of propane </em>= (4032.0 kJ)(0.5 mol)/(2.0 mol) = <em>1008.0 kJ.</em>

8 0
3 years ago
Read 2 more answers
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