It begins by trying to solve a problem and or making a hypothesis.
<span>he density of a material is defined as its mass per
unit volume. In this example, each volume of water is different and
therefore has a specific and unique mass. The mass of water is expressed
in grams (g) or kilograms (kg), and the volume is measured in liters (L), cubic centimeters (cm 3), or milliliters (mL).</span>
There are 22.5 grams of protein in one cup of soup that has 140 kcal with 8 g of carbohydrate and 2 g of fat.
<h3>What is the mass of a substance?</h3>
The mass of a substance is the quantity of the substance that is being measured in grams or kilograms.
To determine the energy from the 8g of carbohydrate, we have:
= 8g × 4 kcal/g (the corresponding calories of food type)
= 32 kcal
The energy from 2g of fat = 2g × 9 kcal/g
= 18 kcal
The energy from protein is calculated as:
= 140 kcal - 32 kcal - 18 kcal
= 90 kcal
The required mass of the protein in grams is:
= 22.5 grams
Therefore, we can conclude that there are 22.5 grams of protein in one cup of soup.
Learn more about the mass of a substance here:
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Answer: 35.4 g
2 moles of phosphorous chloride are produced by = 3 moles of
Thus 0.37 moles of phosphorous chloride are produced by= of
Mass of
Thus 35.4 g of chlorine reacted with the phosphorus
Answer: First, here is the balanced reaction: 2C4H10 + 13O2 ===> 8CO2 + 10H2O.
This says for every mole of butane burned 4 moles of CO2 are produced, in other words a 2:1 ratio.
Next, let's determine how many moles of butane are burned. This is obtained by
5.50 g / 58.1 g/mole = 0.0947 moles butane. As CO2 is produced in a 2:1 ratio, the # moles of CO2 produced is 2 x 0.0947 = 0.1894 moles CO2.
Now we need to figure out the volume. This depends on the temperature and pressure of the CO2 which is not given, so we will assume standard conditions: 273 K and 1 atmosphere.
We now use the ideal gas law PV = nRT, or V =nRT/P, where n is the # of moles of CO2, T the absolute temperature, R the gas constant (0.082 L-atm/mole degree), and P the pressure in atmospheres ( 1 atm).
V = 0.1894 x 0.082 x 273.0 / 1 = 4.24 Liters.
Explanation:
