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Katarina [22]
3 years ago
14

How many moles are in 8.0 x 10^13 atoms of Ag?explain please ​

Chemistry
1 answer:
zubka84 [21]3 years ago
8 0

1.328 × 10⁻¹⁰ Ag atoms

Explanation:

To find the number of moles we use the Avogadro's number to formulate the following reasoning:

if in          1 mole of Ag there are 6.022 × 10²³ Ag atoms

then in    X moles of Ag there are 8 × 10¹³ Ag atoms

X = (1 × 8 × 10¹³) / ( 6.022 × 10²³) = 1.328 × 10⁻¹⁰ Ag atoms

Learn more about:

Avogadro's number

brainly.com/question/1445383

brainly.com/question/13272803

#learnwithBrainly

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How equation can show physical states and reaction conditions
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Answer:

Explanation:

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2 years ago
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List the ions in solution in the electrolysis of conc.sodium chloride<br>​
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2 years ago
Iron is extracted from iron oxide in the Blast Furnace: Fe 2 O 3 + 3 CO → 2 Fe + 3 CO 2
arsen [322]

a. mass of iron = 69.92 g

b. percent yield = 93%

<h3>Further eplanation </h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

a.

Reaction

Fe₂O₃+3CO⇒2Fe+3CO₂

MW Fe₂O₃ :  159.69 g/mol

mol Fe₂O₃

\tt \dfrac{100}{159,69}=0.626

mol Fe₂O₃ : mol Fe = 1 : 2

mol Fe :

\tt \dfrac{2}{1}\times 0.626=1.252

mass of Fe(Ar=55.845 g/mol) :

\tt 1.252\times 55.845=69.92~g

b.

actual yield = 65 g

theoretical yield = 69.92 g

percent yield :

\tt =\dfrac{65}{69.92}=0.93=93\%

8 0
2 years ago
What is the mole ratio of N2 to H2 to NH3?
Alexeev081 [22]

Answer:

the answer is 1:3:2

Hope this helps, let me know if you need any other help, Stoichiometry is hard

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3 years ago
How many moles are in 1.05 g of gold (Au)?
Wittaler [7]

Answer:

0.005 mol

Explanation:

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,  

n = w / m

n = moles ,  

w = given mass ,  

m = molecular mass .

From the question ,

w = given mass of Gold = 1.05 g ,

m = molecular mass of Gold = 197 g/mol

<u>Hence , moles can be calculated as -</u>

n = w / m = 1.05 g / 197 g/mol = 0.005 mol

7 0
2 years ago
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