Write the formula for calcium chloride

What element’s valence electrons are located in 5s25p4?

IrinaK [193]

The element is TELLURIUM. Tellurium has atomic number 52 with the electronic configuration of [Kr] 4d10 5s2 5p4. The element belongs to group 16 elements on the periodic table. It exhibits various oxidation states: +2, +4, +6, and -2. +4 is its most common oxidation state.

5 0

3 years ago

If 1.8 L of water is added to 2.5 L of a 7.0 M KOH solution, what is the molarity of the new solution?

e-lub [12.9K]

Molarity= (number of moles of that substance) / (Volume of solution in litres)

7= (number of moles of HCl) / 0.05

Thus,

Number of moles of HCl = 7 x 0.05 = 0.35

The number of moles of HCl will remain unchanged.

Now, for new solution,

0.35= 0.35 / (New volume of solution in litres)

Thus,

New volume = 1 litre

Thus, amount of water added = 1- 0.05 litre = 5.0 M

6 0

3 years ago

Please help me there is 19 questions

cupoosta [38]

Answer:

1. Hubble

2.Aristarchus

3.Galileo

4.Aristotle

5.Kepler

6.Jupiter

7.Mercury

8.Uranus

9.Venus

10.Earth

11. Jupiter and Mars

12. sun

13.D

14. Saturn

15.Gas giants

16.Kuiper Belt and Ceres,Pluto,eris and haumea.

17.pluto

18.Ptolemy's model

19.meteor- a small body of matter from the outer surface that enters the earth's atmosphere.

meteoroid- a small body moving in the solar system that would become a meteor if it enters the earth's atmosphere.

meteorite- a piece of rock or metal that has fallen to the earth's surface from outer space as a meteor.

the relationship is the diagram I drew at the top.

hope this was helpful

6 0

3 years ago

How many significant figures are in each of the following measurements? (c) 0.03003 kg (f) 3.8200 x 103 L (a) (d) 0.00450 m 35.0

erica [24]

Answer:

c =four significant figures = 3003

f = Four significant figures = 3820

d =(i) three significant figures = 450

d =(ii) Six significant figures = 35.0445

b = significant figures = 59.0001

e = five significant figures = 67000

Explanation:

c = 0.03003 kg

four significant figures = 3003

f = 3.8200 × 10³ L

Four significant figures = 3820

d =(i) 0.00450 m and (ii) 35.0445 g

(i) three significant figures = 450

(ii) Six significant figures = 35.0445

b = 59.0001 cm

six significant figures = 59.0001

e = 67000

five significant figures = 67000

The given measurement have five significant figures 41006. this measurement can be rounded to three significant figures i.e, 0.410 g.

All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.

Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.

Zero between the non zero digits are consider significant like 104 consist of three significant figures.

The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.

8 0

3 years ago

Which set of numbers gives the correct possible values of l for n = 3?

Free_Kalibri [48]

0 1 2 3
0 and 3 is 3
1 and 2 is 3

3 0

3 years ago

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Write the formula for calcium chloride​

Write the formula for calcium chloride