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3 years ago

If (x+1,10)=(4,2y) then find the value of x & y

Mathematics

1 answer:

lawyer [7]3 years ago

3 0

Answer:

Step-by-step explanation:

<h3>Given, </h3>

(x+1, 10) = (4, 2y)

First x coordinate, 

x + 1 = 4

=> x = 4 - 1

=> x = 3 (Ans) (i)

Second y coordinate, 

10 = 2y

$= > y = \frac{10}{2}$

=> y = 5 (Ans) (ii)

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Fill in the missing work and justification for step 3 when solving 2(x + 1) = 10.

kirill115 [55]

Answer:

2(x + 1) = 10

x = 4

Step-by-step explanation:

Given:

2(x + 1) = 10

Solution:

Apply Distributive property

A*(B+C) = (A*B) + (A*C)

This means multiply 2 with x and 1

2*(x+1) = (2*x) + (2*1)

2x + 2 = 10

Use Subtraction property of equality

A = B, then A - C = B - C

Subtracting 2 from both sides:

2x + 2 - 2 = 10 - 2

2x = 8 Step 3

Use Division property of equality

It state that if you divide both sides of an equation by same nonzero number then the sides remain equal

Dividing both sides by 2

2x/2 = 8/2

x = 4

This means value of x is 4

Another method to solve this equation is:

2(x+1)=10

Use Distributive property

A*(B+C) = (A*B) + (A*C)

2*(x+1) = (2*x) + (2*1)

2*(x+1) = 2x + 2

Use commutative property

A + (-B) = (-B) + A

2x + 2 + (-2) = 2x + (-2) + 2

2x + 2 + (-2) = 10 + (-2)

2x + 2 - 2 = 10-2

2x = 8

Using division property

AX = B

AX / A = B / A

X = B/A

This becomes:

2x = 8

2x = 8.

Divide both sides by 2

2x / 2 = 8 / 2

x = 4

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3 years ago

What set of reflections would carry trapezoid ABCD onto itself?

Ne4ueva [31]

Y=x,x-axis,y=x, y-axis

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3 years ago

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yanalaym [24]

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3 years ago

Find the equation of the line passing through point (4,2) and perpendicular to AB

Setler [38]

Answer:

a. -⅓

b. 3

c. y = 3x - 10

Step-by-step explanation:

a. Gradient of line AB:

A(1, 3), B(7, 1)

$Gradient = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 3}{7 - 1} = \frac{-2}{6} = -\frac{1}{3}$

Gradient (m) = -⅓

b. The of the line that is perpendicular to line AB would be the negative reciprocal of the gradient of line AB.

Thus, the negative reciprocal of -⅓ = 3

Gradient of the line perpendicular to line AB = 3

c. Equation of the line that passes through (4, 2) and is perpendicular to line AB:

We can write the equation using the point-slope form equation, y - b = m(x - a), where,

(a, b) represents a point on the line, and,

m = gradient/slope

We know that the gradient/slope (m) = 3

Also, a point, (a, b) = (4, 2).

Therefore, substitute a = 4, b = 2, and m = 3 into y - b = m(x - a)

Thus:

y - 2 = 3(x - 4)

y - 2 = 3x - 12

Add 2 to both sides

y = 3x - 12 + 2

y = 3x - 10

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3 years ago

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ivann1987 [24]

The answer is 221 I did the work

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