Question

an object is sliding down in clean plane the velocity change at a constant rate from 10 cm to 15 CM in 2 second what is it acceleration ?​

Answer 1

Initial velocity=10m/s=u

Final velocity=v=15m/s

Time=t=2s

$\boxed{\sf Acceleration=\dfrac{v-u}{t}}$

$\\ \sf\longmapsto Acceleration=\dfrac{15-10}{2}$

$\\ \sf\longmapsto Acceleration=\dfrac{5}{2}$

$\\ \sf\longmapsto Acceleration=2.5m/s^2$

Answer 2

Answer: a = 2.5 cm/s²

Explanation:

Acceleration = (Final velocity - Initial Velocity)/time taken

a = v-u/t

Initial velocity = 10 cm/s

Final velocity = 15 cm/s

Time = 2 seconds

a = (15-10)/2

a = 5/2

a = 2.5 cm/s²

Therefore the acceleration is 2.5 cm/s²

please click thanks and mark brainliest if you like :)