Answer:
16.732 N
Explanation:
Given:
q1 = 0.00047 C = 4.7 x 10^-4 C
q2 = 0.00089 C = 8.9 x 10^-4 C
d = 15 m
k = 9 x 10^9 N m^2 / C^2
To Find:
F = ?
Solution:
F = k x q1 x q2/d^2
F = 9 x 10^9 x 4.7 x 10^-4 x 8.9 x 10^-4 / 15 x 15
F = 9 x 4.7 x 8.9 x 10^9 x 10^-4 x 10^-4 / 225
F = 9 x 4.7 x 8.9 x 10^9 x 10^-8 / 225
F = 9 x 4.7 x 8.9 x 10 / 225
F = 418.3/25
F = 1673.2/100
Therefore, F = 16.732 N
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Answer:
The correct option is;
D) The force exerted on the astronaut by Earth is equal to the force exerted on Earth by the astronaut
Explanation:
According to Newton's third law of motion, in nature, for every action, there is an equal and opposite reaction, such that if a first object exerts a certain amount of force on a second object, the second object will exert a force of equal magnitude and opposite direction to that exerted by the first object
Therefore, the gravitational force exerted by Earth on the astronaut, is equal to the force exerted by the astronaut on Earth.
Answer:
The answer is D
The second law of thermodynamics
Explanation:
Water evaporates from the surface of the earth and through the leaves of the plants and trees by absorbing the heat energy from the surrounding.
This water then converts into vapour and goes up into the atmosphere where the temperature is low in the troposphere and condenses to form the clouds. During the cloud formation the heat form the vapour is absorbed in the troposphere.
These clouds when get saturated then fall in the form of precipitation of water, snow etc. Replenishing back the water of the earth.
Answer:
The amount of heat transfer is 21,000J .
Explanation:
The equation form of thermodynamics is,
ΔQ=ΔU+W
Here, ΔQ is the heat transferred, ΔU is the change in internal energy, and W is the work done.
Substitute 0 J for W and 0 J for ΔU
ΔQ = 0J+0J
ΔQ = 0J
The change in internal energy is equal to zero because the temperature changes of the house didn’t change. The work done is zero because the volume did not change
The heat transfer is,
ΔQ=Q (in
) −Q (out
)
Substitute 19000 J + 2000 J for Q(in) and 0 J for Q(out)
ΔQ=(19000J+2000J)−(0J)
=21,000J
Thus, the amount of heat transfer is 21,000J .