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anzhelika [568]
3 years ago
5

Taylor wants to find the perimeter of a rectangular playground. The lenght of the playground measures (3x-20) metres. The width

of the playground measures (2x+4) metres. What is the perimeter of the playground? ​
Mathematics
1 answer:
stellarik [79]3 years ago
8 0

Answer:

Step-by-step explanation:

P = 2(3x-20) + 2(2x+4) = (6x-40) + (4x+8) = 10x-32

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The area of a cross section through the center of a sphere is 46 square inches. Find the surface area of the sphere.
gavmur [86]

Answer:

184 in.^2

Step-by-step explanation:

The cross section through the center of a sphere is a circle whose radius is equal to the radius of the sphere.

area of circle

A_{circle} = \pi r^2

\pi r^2 = 46

r^2 = \dfrac{46}{\pi}

r = \sqrt{\dfrac{46}{\pi}}

r = 3.83 ~in.

surface area of sphere

SA = 4 \pi r^2

SA = 4 \times \pi \times (3.83)^2

SA = 184~in.^2

7 0
3 years ago
A used motorcycle is on sale for $3,600. Erik makes an offer equal to 3/4 of this price. How much does Erik offer for the motorc
lesantik [10]
3/4 of 3600..." of " means multiply
3/4 * 3600 =
10800/4 = 
2700 <==

4 0
3 years ago
Read 2 more answers
The price, p, for different size orders of printed programs for a musical production, n, is given in the table.
Leya [2.2K]
The answer is B, hope this helps!
8 0
3 years ago
Read 2 more answers
Diagram 5 shows a triangle ABD such that AD = 17 cm, AB = 10 cm and BD = 21 cm. The straight line AC is perpendicular to the str
OlgaM077 [116]

Answer:

8

Step-by-step explanation:

100 = x^2 + AC^2

17^2 = AC^2 + (21 - x)^2

289 = AC^2 + 21^2 + x^2 - 2*21*x

289 =<u> AC^2</u> + 441 +<u> x^2</u> - 42x

from 1st equation AC^2 + x^2 = 100

289 = 441 + 100 - 42x

289 = 541 - 42x

42x = 541 - 289 = 252

x = 252/42 = 6

so AC^2 = 100 - 6^2 = 100 - 36 = 64

AC = 8

7 0
3 years ago
(1.)What is the value of 35−3m , when m = 4?
Len [333]
(1.) 35-3m
m= 4

35-3m
= 35-3(4)
= 35-12 (do the multiple/division first before doing the addition/subtraction)
= 23

C. 23

(2.) 1 + x ÷ 5
x = 80

1 + x ÷ 5
= 1+80÷5
= 1+16
= 17

(3.) mx-y
m=5, x=3, and y=8

mx-y
= 5(3)-8
= 15-8
= 7

(4.) 3a+15+bc−6
a=7, b=3, and c=15

3a+15+bc-6
= 3(7)+15+3(15)-6
= 21+15+45-6
= 75
4 0
4 years ago
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