Answer:
24.9mL of the stock solution are required
Explanation:
To solve this question we have to find, as first, the moles of HCl that we need to prepare the desire solution. These moles are taken from the stock solution as follows:
<em>Moles diluted solution:</em>
500.0mL = 0.5000L * (0.613mol / L) = 0.3065 moles HCl
As these moles comes from the 12.3M HCl solution, the volume that we need of the stock solution is:
<em>Volume stock solution:</em>
0.3065 moles HCl * (1L / 12.3moles) = 0.0249L 12.3M HCl =
<h3>24.9mL of the stock solution are required</h3>
We are given with
4.35 g Phosphoric acid
5.25 g KOH
3.15 g K3PO4 produced
The reaction is
H3PO4 + 3KOH => K3PO4 + 3H2O
First, convert masses into moles.
Then, determine the limiting reactant.
Next, determine the maximum amount of K3PO4 that can be produced from the limiting reactant.
Lastly, calculate the percent yield by dividing the actual amount produced by the theoretical amount produced.
Answer:
If heart disease is suspected, we use two-dimensional doppler imaging technologies that take in-depth images of the heart. The doppler system records sound waves as they bounce off blood cells in your heart and change pitch. The blood flow shown in these images is colorized to better detect any problems.
Explanation:
First we need to find the moles of Mg(NO_3)_2,

Using the equation for molarity,
, where M is molarity n is number of moles and V is volume. We make V subject and solve

Answer:
in theoretical yield are obtained 2.61 g of aspirin from 2.0 g of salicylic acid and 5 mL of acetic anhydride
Explanation:
Aspirin (C9H8O4)
∴ mm C9H8O4 = 180 g/mol
salicylic acid (C7H6O3)
∴ mm C7H6O3 = 138 g/mol
acetic anhydride (C4H6O3)
∴ mm C4H6O3 = 102 g/mol
acetic acid (C2H4O2)
∴ mm C2H4O2 = 60 g/mol
reaction:
- C7H6O3 + C4H6O3 → C9H8O4 + C2H4O2
∴ g C7H6O3 = 2.0 g
∴ g C4H6O3 = (5.0 mL)(1.08 g/mL) = 5.4 g
limit reagent (L.R):
∴ n C7H6O3 = (2 g)(mol/138 g) = 0.0145 mol C7H6O3 (L.R)
∴ n C4H6O3 = (5.4 g)(mol/102 g) = 0.053 mol C4H6O3 (E.R)
theoretical yield:
Amount of product predicted by balanced equation when all limit reagent reacts
⇒ n C9H8O4 = (0.0145 mol C7H6O3)(mol C9H8O4/mol C7H6O3) = 0.0145 mol C9H8O4
⇒ g C9H8O4 = (0.0145 mol)(180 g/mol) = 2.61 g C9H8O4