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shtirl [24]
3 years ago
12

In an experiment, hydrochloric acid reacted with different volumes of sodium thiosulfate in water. A yellow precipitate was form

ed during the reaction. A cross drawn at
the base of each flask became gradually invisible due the formation of this yellow precipitate. The time taken for the cross to become invisible was recorded. A partial
record of the experiment is shown
Experimental Record

Based on your knowledge of factors that affect the rates of chemical reactions, predict the trend in the last column of the experimental record. Use complete
sentences to explain the trend you predicted. You do not have to determine exact values for time, just describe the trend you would expect (increase or decrease)
and why it occurs

Chemistry
1 answer:
iris [78.8K]3 years ago
6 0

Answer:

I think that the trend that would be seen in the time column of the data table would be that the number of seconds would increase. I know this because for each flask, the concentration of sodium thiosulfate decreases, since less of it is being mixed with more water. Also, when the concentration of a substance decreases, then the reaction rate also decreases, as there will be fewer collisions with sulfuric acid if there are fewer moles of sodium thiosulfate. When there are fewer collisions in a reaction, the reaction itself will take longer, and so when the sodium thiosulfate is diluted, the reaction takes more time.

Explanation:

<em>I verify this is correct. </em>

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Question 27
3241004551 [841]

Answer:

24.9mL of the stock solution are required

Explanation:

To solve this question we have to find, as first, the moles of HCl that we need to prepare the desire solution. These moles are taken from the stock solution as follows:

<em>Moles diluted solution:</em>

500.0mL = 0.5000L * (0.613mol / L) = 0.3065 moles HCl

As these moles comes from the 12.3M HCl solution, the volume that we need of the stock solution is:

<em>Volume stock solution:</em>

0.3065 moles HCl * (1L / 12.3moles) = 0.0249L 12.3M HCl =

<h3>24.9mL of the stock solution are required</h3>
3 0
3 years ago
If 4.35 g of phosphoric acid are added to 5.25g of KOH, what is the percent yield of the reaction if only 3.15g of potassium pho
irina1246 [14]
We are given with
4.35 g Phosphoric acid
5.25 g KOH
3.15 g K3PO4 produced

The reaction is
H3PO4 + 3KOH => K3PO4 + 3H2O

First, convert masses into moles.
Then, determine the limiting reactant.
Next, determine the maximum amount of K3PO4 that can be produced from the limiting reactant.
Lastly, calculate the percent yield by dividing the actual amount produced by the theoretical amount produced.
5 0
3 years ago
Someone please help will mark as brainliest
Flura [38]

Answer:

If heart disease is suspected, we use two-dimensional doppler imaging technologies that take in-depth images of the heart. The doppler system records sound waves as they bounce off blood cells in your heart and change pitch. The blood flow shown in these images is colorized to better detect any problems.

Explanation:

6 0
3 years ago
Read 2 more answers
What volume in L of a 0.32 M Mg(NO3)2 solution contains 45 g of Mg(NO3)2?
ludmilkaskok [199]

First we need to find the moles of Mg(NO_3)_2,

45g Mg(NO_3)_2\times\frac{1mol Mg(NO_3)_2}{148.32g}= 0.3034 mol

Using the equation for molarity, M=\frac{n}{V}, where M is molarity n is number of moles and V is volume. We make V subject and solve

M=\frac{n}{V}\\V=\frac{n}{M}= \frac{0.3034mol}{0.32mol/L}=0.94L

4 0
3 years ago
Read 2 more answers
Identify R and R' in Equation 1 when the ester, aspirin, is made from salicylic acid and acetic acid. (Equation 1) Calculate the
Flauer [41]

Answer:

in theoretical yield are obtained  2.61 g of aspirin from 2.0 g of salicylic acid and 5 mL of acetic anhydride

Explanation:

Aspirin (C9H8O4)

∴ mm C9H8O4 = 180 g/mol

salicylic acid (C7H6O3)

∴ mm C7H6O3 = 138 g/mol

acetic anhydride (C4H6O3)

∴ mm C4H6O3 = 102 g/mol

acetic acid (C2H4O2)

∴ mm C2H4O2 = 60 g/mol

reaction:

  • C7H6O3 + C4H6O3 → C9H8O4 + C2H4O2

∴ g C7H6O3 = 2.0 g

∴ g C4H6O3 = (5.0 mL)(1.08 g/mL) = 5.4 g

limit reagent (L.R):

∴ n C7H6O3 = (2 g)(mol/138 g) = 0.0145 mol C7H6O3 (L.R)

∴ n C4H6O3 = (5.4 g)(mol/102 g) = 0.053 mol C4H6O3 (E.R)

theoretical yield:

Amount of product predicted by balanced equation when all limit reagent reacts

⇒ n C9H8O4 = (0.0145 mol C7H6O3)(mol C9H8O4/mol C7H6O3) = 0.0145 mol C9H8O4

⇒ g C9H8O4 = (0.0145 mol)(180 g/mol) = 2.61 g C9H8O4

6 0
3 years ago
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