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shtirl [24]
2 years ago
12

In an experiment, hydrochloric acid reacted with different volumes of sodium thiosulfate in water. A yellow precipitate was form

ed during the reaction. A cross drawn at
the base of each flask became gradually invisible due the formation of this yellow precipitate. The time taken for the cross to become invisible was recorded. A partial
record of the experiment is shown
Experimental Record

Based on your knowledge of factors that affect the rates of chemical reactions, predict the trend in the last column of the experimental record. Use complete
sentences to explain the trend you predicted. You do not have to determine exact values for time, just describe the trend you would expect (increase or decrease)
and why it occurs

Chemistry
1 answer:
iris [78.8K]2 years ago
6 0

Answer:

I think that the trend that would be seen in the time column of the data table would be that the number of seconds would increase. I know this because for each flask, the concentration of sodium thiosulfate decreases, since less of it is being mixed with more water. Also, when the concentration of a substance decreases, then the reaction rate also decreases, as there will be fewer collisions with sulfuric acid if there are fewer moles of sodium thiosulfate. When there are fewer collisions in a reaction, the reaction itself will take longer, and so when the sodium thiosulfate is diluted, the reaction takes more time.

Explanation:

<em>I verify this is correct. </em>

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An ideal gas (C}R), flowing at 4 kmol/h, expands isothermally at 475 Kfrom 100 to 50 kPa through a rigid device. If the power pr
Zina [86]

<u>Answer:</u> The rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

<u>Explanation:</u>

We are given:

C_p=\frac{7}{2}R\\\\T=475K\\P_1=100kPa\\P_2=50kPa

Rate of flow of ideal gas , n = 4 kmol/hr = \frac{4\times 1000mol}{3600s}=1.11mol/s    (Conversion factors used:  1 kmol = 1000 mol; 1 hr = 3600 s)

Power produced = 2000 W = 2 kW     (Conversion factor:  1 kW = 1000 W)

We know that:

\Delta U=0   (For isothermal process)

So, by applying first law of thermodynamics:

\Delta U=\Delta q-\Delta W

\Delta q=\Delta W      .......(1)

Now, calculating the work done for isothermal process, we use the equation:

\Delta W=nRT\ln (\frac{P_1}{P_2})

where,

\Delta W = change in work done

n = number of moles = 1.11 mol/s

R = Gas constant = 8.314 J/mol.K

T = temperature = 475 K

P_1 = initial pressure = 100 kPa

P_2 = final pressure = 50 kPa

Putting values in above equation, we get:

\Delta W=1.11mol/s\times 8.314J\times 475K\times \ln (\frac{100}{50})\\\\\Delta W=3038.45J/s=3.038kJ/s=3.038kW

Calculating the heat flow, we use equation 1, we get:

[ex]\Delta q=3.038kW[/tex]

Now, calculating the rate of lost work, we use the equation:

\text{Rate of lost work}=\Delta W-\text{Power produced}\\\\\text{Rate of lost work}=(3.038-2)kW\\\text{Rate of lost work}=1.038kW

Hence, the rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

4 0
2 years ago
Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt% methanol and the second contain
RoseWind [281]

Answer:

M_{per}= 52.86

W_{per}=47.14

Explanation:

<u>First mixture</u>:

40 wt% methanol - 60 wt% water 200 kg

m_{met1}=200 kg * 0.4= 80 kg

m_{wat1}=200 kg * 0.6= 120 kg

<u>Second mixture</u>:

70 wt% methanol - 30 wt% water 150 kg

m_{met2}=150 kg * 0.7= 105 kg

m_{wat2}=150 kg * 0.3= 45 kg

Final mixture:

m_{metF=80 kg + 105 kg= 185 kg

m_{watF}=120 kg + 45 = 165 kg

M_{per}=\frac{185 kg}{185 kg + 165 kg}*100= 52.86

W_{per}=\frac{165 kg}{185 kg + 165 kg}*100=47.14

If, the compositions are constant, the only variables are the mass of each mixture used in the final one, so there can be only one independent balance.

8 0
3 years ago
How is condensation explained by the Kinetic Molecular Theory? Cooling reduces particle motion, resulting in coalescence by attr
lara31 [8.8K]

Temperature means, in this context, movement.

Condensation can be explained by the reduction of temperature of the system. This effect make possible the cohesion forces increases. In other words, the result is coalescence by attractive forces.

7 0
3 years ago
Read 2 more answers
Soft of easy help plz<br><br><br><br> B<br><br> C<br><br> A<br><br> D
umka21 [38]

Answer:

C

Explanation:

8 0
3 years ago
Calculate the equilibrium constant for the reaction using the balanced chemical equation and the concentrations of the substance
Oliga [24]

Answer:

4.75 is the equilibrium constant for the reaction.

Explanation:

CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

Equilibrium concentration of reactants :

[CO]=0.0590 M,[H_2O]=0.00600 M

Equilibrium concentration of products:

[CO_2]=0.0410 M,[H_2]=0.0410 M

The expression of an equilibrium constant is given by :

K_c=\frac{[CO_2][H_2]}{[CO][H_2O]}

K_c=\frac{0.0410 M\times 0.0410 M}{0.0590M\times 0.00600 M}

K_c=4.75

4.75 is the equilibrium constant for the reaction.

3 0
2 years ago
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