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Maru [420]
3 years ago
7

Hellppppp

Chemistry
1 answer:
Margaret [11]3 years ago
8 0

Answer:

c

Explanation:

you don't think of particles as dense and less dense

dust particles containvenergy but won't release it unless acted upon a force

gas molecules move freely and collide with dust particles which is correct

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Describe the ammonium ion, NH4+, and the sulfate ion, SO42-. What compounds would these ions form with potassium and fluoride io
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<span>Cations mix with anions, so you know NH4+ won't mix with K+ and SO4(2-) won't miix with F-. For the reason that NH4+ and F- together have single charges, they'll mix in a 1:1 ratio, NH4F. There's two charges on SO4(2-), so it'll need two K+ to mix with, K2SO4.</span>
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How is it possible to have thousands of different proteins when there are only 20 different amino acids?
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Although there are only 20 amino acids, these amino acids can combine into an innumerable amount of combinations to form different and unique proteins. 

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3 years ago
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3 0
3 years ago
Cần bao nhiêu gam KMnO4 và bao nhiêu mililit dung dịch axit clohiddric 1M để điều chế đủ khí clo tác dụng với sắt , tạo nên 16,2
Verdich [7]

Answer:

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6 0
3 years ago
Cuando se quema 1 mol de metano –o sea, 16 g–, se desprenden 802
Anvisha [2.4K]

Answer:

1 gramo de metano aporta 50.125 kilojoules.

1 gramo de metano aporta 48.246 kilojoules.

Explanation:

La cantidad de energía liberada por la combustión de una unidad de masa del hidrocarburo (Q), en kilojoules por mol, es igual a la cantidad de energía liberada por mol de compuesto (\bar {Q}), en kilojoules por mol, dividido por su masa molar (M), en gramos por mol:

Q = \frac{\bar Q}{M} (1)

A continuación, analizamos cada caso:

Metano

Q = \frac{802\,\frac{kJ}{mol} }{16\,\frac{g}{mol} }

Q = 50.125\,\frac{kJ}{g}

1 gramo de metano aporta 50.125 kilojoules.

Octano

Q = \frac{5500\,\frac{kJ}{mol} }{114\,\frac{g}{mol} }

Q = 48.246\,\frac{kJ}{mol}

1 gramo de metano aporta 48.246 kilojoules.

3 0
3 years ago
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