425 g X 1 mL/.92 g = 462 mL
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An ion with fewer electrons than its neutral atom is called a(n) cation. The charge of an ion with more electrons than its neutral atom is. negative.
Use the coefficients in front of each element or compound
in this case 2 1 2
Answer : The change in internal energy and change in enthalpy of the gas is 1143.2 J/mol and 1600.5 J/mol respectively.
Explanation :
(a) The formula used for change in internal energy of the gas is:
![\Delta U=C_v\Delta T\\\\\Delta U=C_v(T_2-T_1)](https://tex.z-dn.net/?f=%5CDelta%20U%3DC_v%5CDelta%20T%5C%5C%5C%5C%5CDelta%20U%3DC_v%28T_2-T_1%29)
where,
= change in internal energy = ?
= heat capacity at constant volume = ![20.785J/mol.K](https://tex.z-dn.net/?f=20.785J%2Fmol.K)
= initial temperature = ![5^oC=273+5=278K](https://tex.z-dn.net/?f=5%5EoC%3D273%2B5%3D278K)
= final temperature = ![60^oC=273+60=333K](https://tex.z-dn.net/?f=60%5EoC%3D273%2B60%3D333K)
Now put all the given values in the above formula, we get:
![\Delta U=nC_v(T_2-T_1)](https://tex.z-dn.net/?f=%5CDelta%20U%3DnC_v%28T_2-T_1%29)
![\Delta U=(20.785J/mol.K)\times (333-278)K](https://tex.z-dn.net/?f=%5CDelta%20U%3D%2820.785J%2Fmol.K%29%5Ctimes%20%28333-278%29K)
![\Delta U=1143.175J/mol\approx 1143.2J/mol](https://tex.z-dn.net/?f=%5CDelta%20U%3D1143.175J%2Fmol%5Capprox%201143.2J%2Fmol)
The change in internal energy of the gas is 1143.2 J/mol.
(b) The formula used for change in enthalpy of the gas is:
![\Delta H=C_p\Delta T\\\\\Delta H=C_p(T_2-T_1)](https://tex.z-dn.net/?f=%5CDelta%20H%3DC_p%5CDelta%20T%5C%5C%5C%5C%5CDelta%20H%3DC_p%28T_2-T_1%29)
where,
= change in enthalpy = ?
= heat capacity at constant pressure = ![29.100J/mol.K](https://tex.z-dn.net/?f=29.100J%2Fmol.K)
= initial temperature = ![5^oC=273+5=278K](https://tex.z-dn.net/?f=5%5EoC%3D273%2B5%3D278K)
= final temperature = ![60^oC=273+60=333K](https://tex.z-dn.net/?f=60%5EoC%3D273%2B60%3D333K)
Now put all the given values in the above formula, we get:
![\Delta U=nC_v(T_2-T_1)](https://tex.z-dn.net/?f=%5CDelta%20U%3DnC_v%28T_2-T_1%29)
![\Delta U=(29.100J/mol.K)\times (333-278)K](https://tex.z-dn.net/?f=%5CDelta%20U%3D%2829.100J%2Fmol.K%29%5Ctimes%20%28333-278%29K)
![\Delta U=1600.5J/mol](https://tex.z-dn.net/?f=%5CDelta%20U%3D1600.5J%2Fmol)
The change in enthalpy of the gas is 1600.5 J/mol.