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Damm [24]
3 years ago
12

Help ASAP,

Chemistry
1 answer:
zhuklara [117]3 years ago
7 0

Answer:

Energy absorbed by <u>Iron block</u> E (iron) = 460.5 J

Energy absorbed by <u>Copper block</u> E (Copper) = 376.8 J

Explanation:

To find the heat absorbed, we can use the formula as,

<em>q = m c ΔT</em>

Here, Mass = m = 10 g = 0.01 kg

ΔT = change in temperature = 400 - 300 = 100 K = 100 - 273 = -173 °C

c = specific heat capacity

c for iron = 460.5 J/kg K

c for copper = 376.8 J/kg K

Plugin the values in the above equation, we will get,

<em>q (iron) = 0.01 kg × 460.5 J/kg K × 100 K            = 460.5 J</em>

<em>q (copper) = 0.01 kg ×  376.8 J/kg K × 100 K                 = 376.8 J</em>

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For the first one, you have to find one that has both a metal and a nonmetal in it, plus potassium. Bonds between nonmetals are called covalent because they share electrons and a bond between a metal and a nonmetal is an ionic bond because they exchange electrons.

Potassium chloride is KCl. Only an ionic bond.

Potassium hydride is KH. Only an ionic bond.

Potassium nitrate is KNO3. There we go, that has a covalent bond between the nitrogen and oxygen, and an ionic bond between potassium and the nitrogen and oxygen.

For the second one, potassium chloride is the answer because the other three also have covalent bonds. Chloride is the only one that isn't a compound.

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2 years ago
These traits describe either a chemical or a nuclear reaction. Which statements describe a nuclear reaction? Check all that appl
Ugo [173]

The statements that describe a nuclear reaction are may involve a change in total mass, involve very high-energy changes, and involve changes in nuclides when decay takes place.  

There are two kinds of nuclear reactions, that is, fission and fusion. Fusion involves the fusion of two light atoms into a heavier atom, while fission involves the splitting of an unstable isotope (with a high mass number) into stable elements of lower mass number, which vary in features from the parent atoms. Both the reactions discharge huge concentration of energies in the process.  


6 0
3 years ago
Read 2 more answers
Determine whether the graph is that of a function by using the vertical-line test. If it is, use the graph to find (a) its domai
Ilia_Sergeevich [38]

Answer:

Following are the solution to this question:

Explanation:

If the draw a line perpendicular with y-axis thru the diagonal line check but it meets only one curved point, therefore the curve indicates a function not otherwise.  They draw a vertical line perpendicular to the y-axis there, it just intersects one more chart point, which is why a graph is a feature:

In point a:

\to Domain= [-\pi ,\pi ]\\\\\to Range = [-1,1]

In point b:

Its y-axis length cut also by understanding the benefits of y-interception and the x-axis length gives the x-intercept.  

\to y-intercept = 1\\\\\to x-intercept = \frac{\pi}{2} ,- \frac{\pi}{2} \\\\

In point C:

Every graph is y-axis symmetric because the left side of the column as well as the middle side of the graph is about the same.

3 0
2 years ago
Draw corresponding structure of 1-cyclophentylhexane.​
I am Lyosha [343]

Answer:

Hexane is a 6-carbon hydrocarbon.

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Two ways of drawing the structure of 1-cyclopentylhexane are below:

3 0
10 months ago
Compared to the freezing point of 1.0 M KCl(aq) at standard pressure, the freezing point of 1.0 M CaCl2(aq) at standard pressure
Galina-37 [17]

Answer : The correct option is, (1) lower

Explanation :

Formula used for lowering in freezing point :

\Delta T_f=i\times k_f\times m

where,

\DeltaT_b = change in freezing point

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i = Van't Hoff factor

According to the question, we conclude that the molality of the given solutions are the same. So, the freezing point depends only on the Van't Hoff factor.

Now we have to calculate the Van't Hoff factor for the given solutions.

(a) The dissociation of KCl will be,

KCl\rightarrow K^++Cl^-

So, Van't Hoff factor = Number of solute particles = 1 + 1 = 2

(b) The dissociation of CaCl_2 will be,

CaCl_2\rightarrow Ca^{2+}+2Cl^-

So, Van't Hoff factor = Number of solute particles = 1 + 2 = 3

The freezing point depends only on the Van't Hoff factor. That means higher the Van't Hoff factor, lower will be the freezing point and vice-versa.

Thus, compared to the freezing point of 1.0 M KCl(aq) at standard pressure, the freezing point of 1.0 M CaCl_2(aq) at standard pressure is lower.

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