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Damm [24]
3 years ago
12

Help ASAP,

Chemistry
1 answer:
zhuklara [117]3 years ago
7 0

Answer:

Energy absorbed by <u>Iron block</u> E (iron) = 460.5 J

Energy absorbed by <u>Copper block</u> E (Copper) = 376.8 J

Explanation:

To find the heat absorbed, we can use the formula as,

<em>q = m c ΔT</em>

Here, Mass = m = 10 g = 0.01 kg

ΔT = change in temperature = 400 - 300 = 100 K = 100 - 273 = -173 °C

c = specific heat capacity

c for iron = 460.5 J/kg K

c for copper = 376.8 J/kg K

Plugin the values in the above equation, we will get,

<em>q (iron) = 0.01 kg × 460.5 J/kg K × 100 K            = 460.5 J</em>

<em>q (copper) = 0.01 kg ×  376.8 J/kg K × 100 K                 = 376.8 J</em>

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Sodium hydroxide, NaOH, reacts with sulfuric acid, H,SO,, in a neutralization reaction to
RSB [31]

Answer:

10.6 grams is approximately 0.10 moles. So you would need about 0.10 moles of sulfuric acid. That converts to about 9.80 grams.

Explanation:

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7 0
3 years ago
How many moles of Co2 are produced when 0.2 moles of sodium carbonate reacts with excess HCl
Pie
To determine the number of moles of carbon dioxide that is produced, we need to know the reaction of the process. For the reaction of HCl and sodium carbonate, the balanced chemical equation would be expressed as:

2HCl + Na2CO3 = 2NaCl + H2O + CO2

From the initial amount given of sodium carbonate and the relation of the substances from the balanced reaction, we calculate the moles of carbon dioxide as follows:

0.2 moles Na2Co3 ( 1 mol CO2 / 1 mol Na2Co3 ) = 0.2 moles CO2

Therefore, the amount in moles of carbon dioxide that is produced from 0.2 moles sodium carbonate would be 0.2 moles as well.
5 0
3 years ago
Which gas will effuse at the rate closest At a particular pressure and temperature, nitrogen gas effuses at the rate of 79mLs. U
Contact [7]

Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}       ..........(1)

where,

R_1 = rate of effusion of nitrogen gas = 79mL/s

R_2 = rate of effusion of sulfur dioxide gas = ?

M_1 = molar mass of nitrogen gas  = 28 g/mole

M_2 = molar mass of sulfur dioxide gas = 64 g/mole

Now put all the given values in the above formula 1, we get:

(\frac{79mL/s}{R_2})=\sqrt{\frac{64g/mole}{28g/mole}}

R_2=52mL/s

Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.

4 0
3 years ago
On the periodic table, in which period is copper?
Firdavs [7]

Answer:

At the top of Group 11 above silver and gold.

Period 4

Explanation:

3 0
3 years ago
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