All categories

3 years ago

Help ASAP,

Chemistry

1 answer:

zhuklara [117]3 years ago

7 0

Answer:

Energy absorbed by Iron block E (iron) = 460.5 J

Energy absorbed by Copper block E (Copper) = 376.8 J

Explanation:

To find the heat absorbed, we can use the formula as,

q = m c ΔT

Here, Mass = m = 10 g = 0.01 kg

ΔT = change in temperature = 400 - 300 = 100 K = 100 - 273 = -173 °C

c = specific heat capacity

c for iron = 460.5 J/kg K

c for copper = 376.8 J/kg K

Plugin the values in the above equation, we will get,

q (iron) = 0.01 kg × 460.5 J/kg K × 100 K = 460.5 J

q (copper) = 0.01 kg × 376.8 J/kg K × 100 K = 376.8 J

You might be interested in

Consider the following system at equilibrium:

elena-14-01-66 [18.8K]

Answer:

Increase D ⇒ rightward shift

Increase E ⇒ rightward shift

Increase F ⇒ leftward shift

Decrease D ⇒ leftward shift

Decrease E ⇒ leftward shift

Decrease F ⇒ rightward shift

Triple D and reduce E to one third ⇒ no shift

Triple both E and F ⇒ no shift

Explanation:

Changes in the concentrations of reactants y products affect to the equilibrium. In this case, D and E are reactants and F is the product.

When a change in the factors affecting equilibrium occur, the system will react in order to counteract the change imposed.

If a increase of reactant occur, the system will tend to produce more products (rightward shift). For example: increase D, increase E. In contraposition, if a decrease of reactant occur, the system will produce more reactants (leftward shift). For example: decrease D, decrease E.

If a increase of product occur, the system will tend to produce more reactants (leftward shift). For example: increase F. In contraposition, if a decrease of product occur, the system will produce more products (rightward shift). For example: decrease F.

If we change both reactants and products concentration in the same amount, the net change is zero, so there is not shift. For example: Triple D and reduce E to one third (D x 3 and E/3, there is not change in the total amount of reactants) ; Triple both E and F (E x 3 and F x 3, the net change is zero).

8 0

3 years ago

If 10.g of AgNo3 is available, what volume of 0.25 M AgNo3 can be prepared

Marianna [84]

The equation is L = m/M
First, covert 10. grams of AgNO3 to moles which is 0.059 moles.
Divide 0.059 moles by 0.25M which is 0.24 liters.

3 0

4 years ago

Which of the following processes includes all of the others? Group of answer choices transport of an ion down its electrochemica

Sever21 [200]

Answer:

Passive transport

Explanation:

In Passive transport the energy is not essential in other for transportation to take place.it is in active transport where you see the need of energy for the process to take place.Passive transport involves the action of facilitated diffusion and osmosis.

3 0

3 years ago

How many moles of Ba(NO3)2 are there in 0. 25 L of a 2. 00 M Ba(NO3)2 solution? Use Molarity equals StartFraction moles of solut

ANEK [815]

The moles of barium nitrate in the solution has been 0.5 mol. Thus, the correct option is B.

Molarity has been defined as the moles of substance in a liter of solution. Molarity has been expressed as:

$\rm Molarity=\dfrac{Moles}{Volume}$