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3 years ago

What is the difference between gross anatomy and microscopic anatomy?

Physics

2 answers:

Simora [160]3 years ago

7 0

Answer:

The gross (or macroscopic) anatomy: The study of anatomical features visible to the naked eye, such as internal organs and external features.

The microscopic anatomy: The study of minute anatomical structures on a microscopic scale, including cells (cytology) and tissues (histology).

Maurinko [17]3 years ago

5 0

There are two major types of anatomy. Gross (macroscopic) anatomy is the study of anatomical structures that can be seen by the eye, such as the external and internal bodily organs. Microscopic anatomy is the study of tiny anatomical structures such as tissues and cells.

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When Danny Diver who weighs 500 N steps off a diving board 10 m above the water, he hits the water with kinetic energy of

Andreas93 [3]

Answer:

5000 J

Explanation:

Given that,

Weight of Danny Diver, F = 500 N

He steps off a diving board 10 m above the water

We need to find the kinetic energy of the water with which it hits. Let its is K. It is given by :

E = mgh

Where g is acceleration due to gravity

$E=500\ N\times 10\ m\\\\=5000\ J$

So, he hits the water with kinetic energy of 5000 J.

8 0

3 years ago

How long has eggs been around

Paraphin [41]

Answer:

About six million years

Explanation:

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3 years ago

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What are the uses of nuclear fission or fusion and their benefits

tamaranim1 [39]

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Hopefully this helps you my dear friend! :-)

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4 years ago

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During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 6.82 s, how high does it rise? The accel

scoray [572]

The answer is 56.98 m

The dislocation (d) is:
d = v1 * t + 1/2 * a * t²
v1 - initial velocity
t - time
a - <span>acceleration of gravity

We know:
d = ?
v1 = ?
t = 6.82 s / 2 = 3.41 (it reaches the peak at half time)
a = - 9.8 m/s</span>²

Let's first calculate v1:
v2 = v1 + at
v2 - final velocity (v2 = 0 when it reaches peak)

0 = v1 + -9.8 * 3.41
0 = v1 - 33.418

v1 = 33.418 m/s

d = v1 * t + 1/2 * a * t²
d = 33.418 * 3.41 + 1/2 * -9.8 * 3.41²
d = 113.96 - 56.98
d = 56.98 m

8 0

4 years ago

A 75.0 kg ladder that is 3.00 m in length is placed against a wall at an angle theta. The center of gravity of the ladder is at

SOVA2 [1]

Answer:

The minimum angle the ladder makes with the horizontal for the ladder not to slip and fall is 45 degrees.

Explanation:

Given that,

Mass of the ladder, m = 75 kg

Length of the ladder, l = 3 m

The center of gravity of the ladder is at a point 1.2 m from the base of the ladder.

The coefficient of static friction at the base of the ladder is 0.4

We need to find the minimum angle the ladder makes with the horizontal for the ladder not to slip and fall.

At equilibrium, net force and net torque on the ladder is equal to zero. Force is given by :

$f=\mu mg$

Using condition for torque as :

$mg\times 12\cos\theta-fl\sin (180-\theta)=0\\\\mg\times 1.2\cos\theta-\mu mgl\sin (180-\theta)=0\\\\\tan\theta=\dfrac{1.2}{\mu l}\\\\\tan\theta=\dfrac{1.2}{0.4\times 3}\\\\\tan\theta=1\\\\\theta=45^{\circ}$

So, the minimum angle the ladder makes with the horizontal for the ladder not to slip and fall is 45 degrees.

4 0

3 years ago