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3 years ago

What is the difference between gross anatomy and microscopic anatomy?

Physics

2 answers:

Simora [160]3 years ago

7 0

Answer:

The gross (or macroscopic) anatomy: The study of anatomical features visible to the naked eye, such as internal organs and external features.

The microscopic anatomy: The study of minute anatomical structures on a microscopic scale, including cells (cytology) and tissues (histology).

Maurinko [17]3 years ago

5 0

There are two major types of anatomy. Gross (macroscopic) anatomy is the study of anatomical structures that can be seen by the eye, such as the external and internal bodily organs. Microscopic anatomy is the study of tiny anatomical structures such as tissues and cells.

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What are the 2 forms of memory retrieval?

Alika [10]

recall and recognition

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4 years ago

Suppose that a 1000 kg car is traveling at 25 m/s (aprox 55mph). Its brakes can apply a force of 5000N. What is the minimum dist

Brrunno [24]

Assuming the the car is travelling to the right (→):

$R(\rightarrow), F = ma$

$\implies a = \frac{F}{m}$

$= \frac{-5000}{1000}$

$= -5 \ ms^{-2}$

The information we know:

$u = 25 \ ms^{-1}$

$v = 0$

$a = -5 \ ms^{-2}$

Using one of the equations of motion:

$v^2 = u^2 + 2as$

$\implies s = \frac{v^2 -u^2}{2a}$

$= \frac{0^2 - 25^2}{2\times (-5)}$

$= \frac{625}{10}$

$= 62.5\ m$

8 0

3 years ago

Read 2 more answers

Which of Newton's laws explains why satellites need very little fuel to stay in oribit?

Angelina_Jolie [31]

Sattelites don't need any fuel to stay in orbit. The applicable law is...."objects in motion tend to stay in motion". Having reached orbital velocity, any such object is essentially "falling" around the earth. Since there is no (or at least very little) friction in the vacuum of space, the object does not slow.... It simply continues.

Sattelites in "low" earth orbit do encounter some friction from the very thin upper atmosphere, and they will eventually "decay".

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3 years ago

Calculate the force between two objects that have masses of 75. Kilograms and 2,100. Kilograms. Their centers of gravity are sep

scoundrel [369]

Answer:

use the formula above it's easy

3 0

2 years ago

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Now Abel and Kato use what they learned to answer the following problem. The initial speed of a tennis ball is 54 m/s and the la

34kurt

Answer:

h=19.4m

R=199.07 m

Explanation:

To solve this problem we use the parabolic motion equations:

We define:

$v_{i}$ total initial speed =54 $\frac{m}{s}$

$\alpha$ =angle that forms the total initial speed with the horizontal line= 21°

$v_{ix}$ :initial speed component in horizontal direction

= $v_{i} cos\alpha$ =54*cos 21= 50.41 m/s

$v_{iy}$ :initial speed component in vertical direction

= $v_{i} sin\alpha$ =54*sin21=19.35 m/s

$v_{x}$ :horizontal speed at any point on the parabolic path

$v_{y}$ : vertical speed at any point on the parabolic path

g= acceleration of gravity= 9,8 $\frac{m}{s^{2} }$

Equation of the speed of the football in the vertical direction :

$(v_{y} )^{2} =(v_{yi} )^{2} -2*g*y$ Equation (1)

Calculation of the maximum height(h)

The speed of the ball (vy) in the vertical direction gradually decreases until its value is zero when it reaches the maximum height.

We replace y=h, $v_{y} =0$ , $v_{iy} = 19.39\frac{m}{s}$ , $g=9.8\frac{m}{s^{2} }$ in the equation(1)

$0=19.35^{2} -2*9.8*h$

$h=\frac{19.35^{2} }{2*9.8}$

h=19.1 m

Calculating of the range (R)

Fórmula: $R=v_{ix} *t (m)$ Equation (2)

R is the maximum horizontal distance the ball reaches.

The time (t) for the ball to reach R is twice the time the ball spends to reach the maximum height. Then, we calculate the time $(t_{h} )$ ) when the ball reaches the maximum height