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Agata [3.3K]
3 years ago
15

28.25 mL, three signicant digits

Physics
2 answers:
Mazyrski [523]3 years ago
3 0

Answer:3) variable affinities (stickiness) for something it is running past. Physical ... -measurement number (significant digits) unit (such as inches) -Significant ... Mass 1 oz. 28.25 g. Relations Between English and Metric Units Mass 1 dram. 1.772 g ... -graduated cylinder has an error of about 1% (± 0.1 mL in 10 mL). -Volumetric

Explanation:

Nutka1998 [239]3 years ago
3 0

Answer:

1. 28.25 mL, three significant digits.

2. 54.074 mL, three significant digits

3. 600.006 km, four significant digits

4. 1356 kg + 4.2 kg + 19.891 kg

Explanation:

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Afina-wow [57]
Answer and working shown on photo, final answer for number electrons=2.5*10^17 electrons

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3 years ago
List down the procedures for each swimming stroke 1.Crawl 2.Breaststoke 3.Butterflystroke 4. Backstoke​
Elena L [17]

Answer: Swimming strokes are techniques that includes arm and leg movements to help push the swimmer against water and propel the swimmer forward.

Explanation:

There are different types of swimming strokes these includes:

--> FRONT CRAWL: This is the fastest of all the techniques. The procedure includes:

• the body is kept flat, facing down and in line with the water surface,

• As the swimmer proceeds with movements, the arms are alternately moved in a PULL (with your palms facing down pull in line with the body) and RECOVERY (with the hand closed to the upper thigh, lift one arm out of the water with a bent elbow) actions.

• As you finish the recovery phase, turn quickly side ways to take in some air.

• With ankles relaxed and flexible, point your toes behind you and kick up-and-down in a continuous motion from your thighs.

BUTTERFLY STROKE: The procedures for this technique includes:

• the body is kept flat, facing down and in line with the water surface.

• the arms are moved in three ways, the catch, pull and recovery movements. The Catch involves the arms being straight, shoulder width apart and palms facing down wards, press down and out against the water with both hands at the same time. The pull involves the hands being pulled towards the body in a semicircular motion. The recovery starts at the end of each pull, the arms are moved out and over the water simultaneously and is thrown forward into the starting position.

• the chin is being raised up at the recovery stage to draw in a breath while looking straight.

• With both legs together and toes pointed, kick downwards at the same time.

• the body is moved in a wave-like manner.

BREASTSTROKE: The procedure for this technique includes;

• the body is kept flat, facing down and in line with the water surface

• the arms are also moved in three ways. In the catch movements, with arms out straight and palms facing downwards, press down and out at the same time. With elevated elbows above the arms, pull hard towards the chest. Then while recovering, to reduce drag when pushing against water, the both palms are joined together Infront of the chest and pushed out until the arms are straight again.

• the head is lifted above water at the end of pulling movement to breath in air.

• bend your knees to bring your heel towards your bottom and make a circular motion outwards with your feet until they return to the starting position.

BACKSTROKE: The procedure for this technique includes

• the body kept flat while backing the water surface. But following the arm movement, it rows from side to side.

• the arms performs alternating and opposite movements. As one arm pulls backwards in the water the other arm recovers above the water.

• taking in air should be alternated with the arm movements.

• the legs are moved up and down in a quick succession to enhance movements.

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3 years ago
Why does it rain more in West Ferris than in East Ferris? Explain your answer.
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Answer:

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Explanation:

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You push a 85 kg shopping cart from rest with a net force of 250 n for 5 seconds,at which point it flies off a cliff that is 100
Vikki [24]

m = mass of the cart = 85 kg

F = net force on the cart = 250 N

a = acceleration of the cart

acceleration of the cart is given as

a = F/m

a = 250/85

a = 2.94 m/s²

t = time for which the force is applied = 5 sec

v₀ = initial velocity of the cart = 0 m/s

v = final velocity of the cart just before  it flies off the cliff = ?

using the equation

v = v₀ + a t

inserting the values

v = 0 + (2.94) (5)

v = 14.7 m/s

consider the motion of cart after it flies off the cliff in vertical direction :

v' = initial velocity in vertical direction = 0 m/s

a' = acceleration in vertical direction = g = acceleration due to gravity = 9.8 m/s²

t' = time taken for the cart to land = ?

Y' = vertical displacement of the cart = height of cliff = 100 m

using the kinematics equation

Y' = v' t' + (0.5) a' t'²

100 = (0) t' + (0.5) (9.8) t'²

t' = 4.52 sec


consider the motion of cart along the horizontal direction after it flies off the cliff

X = distance traveled from the base of cliff = ?

t' = time of travel = 4.52 sec

v = velocity along the horizontal direction = 14.7 m/s

distance traveled from the base of cliff is given as

X = v t'

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3 years ago
Calculate the size of the image of a tree that is 8m high and 80 m a pinhole camera that is 20 cm long . what is its magnificati
Vladimir79 [104]

1) Size of the image: 2 cm

In order to calculate the size of the image, we can use the following proportion:

p:q = h_o : h_i

where

p = 80 m is the distance of the tree from the pinhole

q = 20 cm = 0.2 m is the distance of the image from the pinhole

h_o = 8 m is the heigth of the object

h_i is the height of the image

By re-arranging the proportion, we find

h_i = \frac{h_o \cdot q}{p}=\frac{(8 m)(0.2 m)}{80 m}=0.02 m=2 cm


2) Magnification: 0.0025

The magnification of a camera is given by the ratio between the size of the image and the size of the real object:

M=\frac{h_i}{h_o}

so, in this problem we have

M=\frac{0.02 m}{8 m}=0.0025


4 0
3 years ago
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