It’s A. The moon passes between the earth and sun
Answer:
1,211.1 kg.
Explanation:
the force of gravity is less on the moon than on earth, so if the man can lift 200kg on earth, he could lift a greater amount on the moon because there is less resistance from gravity.
To know the amount of mass he can lift on the moon, we first need to know the amount of weight that is equivalent to those 200kg here on earth. This because the weight of the object is equal to the force that must be applied to lift it, and that force is applied by the man and it will be the same here and on the moon.
We calculate weight using the formula:
where
is the weight of the object (the force with which the earth attracts the object)
is the mass and g the acceleration of gravity.
so

for earth the acceleration due to gravity is: 
thus:

now we use this value to calculate the mass he can lift on the moon, since for the moon
.
we use the same equation, w =mg substituting w = 1962N and
:

he can lift 1,211.1 kg.
You can also find the result using the approximate value of the acceleration of gravity on the moon as g/6, where g is the acceleration on earth.
<h2>The frequency depends upon the source energy of electromagnetic waves</h2>
Explanation:
The energy of electromagnetic wave is
E = h ν
E is the energy of source emitting the waves
here h is Plank's constant
and ν is used for the frequency of the electromagnetic wave
Thus the frequency of wave depends upon the energy of electromagnetic source . Because h is constant .
Answer:
15 N and 3.061
Explanation:
From the question,
The minimum force of friction to keep the book from sliding = 15 N.
using
F = mgμ................. Equation 1
Where F = Frictional Force, m = mass of the book, g = acceleration due to gravity, μ = coefficient of friction.
make μ the subject of the equation
μ = F/mg............... Equation 2
Given: F = 15 N, m = 0.5 kg, g = 9.8 m/s²
Substitute into equation 2
μ = 15(0.5×9.8)
μ = 15/4.9
μ = 3.061
Hence the coefficient of friction to keep the book from sliding = 3.061