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snow_lady [41]
4 years ago
7

2 Why don't all communication devices function off the same wavelength?

Physics
1 answer:
Nostrana [21]4 years ago
7 0

Wavelength is the distance between identical points in the adjacent cycles of a waveform signal propagated in space or along a wire. In wireless systems, this length is usually specified in meters, centimeters, or millimeters.

Wavelengths are an important factor in Wi-Fi networks. Wi-Fi operates at five frequencies, all in the gigahertz range: 2.4 GHz, 3.6 GHz, 4.9 GHz, 5 GHz and 5.9 GHz. Higher frequencies have shorter wavelengths, and signals with shorter wavelengths have more trouble penetrating obstacles like walls and floors.

As a result, wireless access points that operate at higher frequencies with shorter wavelengths, often consume more power to transmit data at similar speeds and distances achieved by devices that operate at lower frequencies, with longer wavelengths.

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During a solar eclipse
raketka [301]
It’s A. The moon passes between the earth and sun
4 0
3 years ago
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A man can lift a mass of 200kg onThe surface of the earth. what is the amount of mass he can lift on the surface of the moon?
Arlecino [84]

Answer:

1,211.1 kg.

Explanation:

the force of gravity is less on the moon than on earth, so if the man can lift 200kg on earth, he could lift a greater amount on the moon because there is less resistance from gravity.

To know the amount of mass he can lift on the moon, we first need to know the amount of weight that is equivalent to those 200kg here on earth. This because the weight of the object is equal to the force that must be applied to lift it, and that force is applied by the man and it will be the same here and on the moon.

We calculate weight using the formula:

w=mg

where w is the weight of the object (the force with which the earth attracts the object) m is the mass and g the acceleration of gravity.

so

w=200g

for earth the acceleration due to gravity is:  g=9.81m/s^2

thus:

w=(200kg)(9.81m/s^2)\\w=1962N

now we use this value to calculate the mass he can lift on the moon, since for the moon g=1.62m/s^2.

we use the same equation, w =mg substituting w = 1962N and g=1.62m/s^2:

w=mg\\\\1962N=m(1.62m/s^2)\\\\m=\frac{1962N}{1.62m/s^2}\\\\ m=1,211.1kg

he can lift 1,211.1 kg.

You can also find the result using the approximate value of the acceleration of gravity on the moon as g/6, where g is the acceleration on earth.

8 0
4 years ago
4. Which of the following statements about the state of matter is correct? A. Molecules in a solid are disorderly arranged B. So
Zolol [24]

Answer:

B. Solids are highly compressible

6 0
3 years ago
What determines the frequency of an electromagnetic wave
Ostrovityanka [42]

<h2>The frequency depends upon the source energy of electromagnetic waves</h2>

Explanation:

The energy of electromagnetic  wave is

E  = h ν

E is the energy of source emitting the waves

here h is Plank's constant

and ν is used for the frequency of the electromagnetic wave

Thus the frequency of wave depends upon the energy of electromagnetic source . Because h is constant .

5 0
3 years ago
When 15 newtons of force is applied to the 0.5 kg book, the friction keeps the book from sliding down the wall. What is the mini
valkas [14]

Answer:

15 N and 3.061

Explanation:

From the question,

The minimum force of friction to keep the book from sliding = 15 N.

using

F = mgμ................. Equation 1

Where F = Frictional Force, m = mass of the book, g = acceleration due to gravity, μ = coefficient of friction.

make μ the subject of the equation

μ = F/mg............... Equation 2

Given: F = 15 N, m = 0.5 kg, g = 9.8 m/s²

Substitute into equation 2

μ = 15(0.5×9.8)

μ = 15/4.9

μ = 3.061

Hence the coefficient of friction to keep the book from sliding = 3.061

4 0
4 years ago
Read 2 more answers
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