Answer:
y = (x+3)^2 -1
Step-by-step explanation:
The vertex form of the equation is
y = a(x-h)^2 +k where (h,k) is the vertex
The vertex is (-3,-1)
y = a(x- -3)^2 -1
y = a(x+3)^2 -1
Pick another point (-2,0) and substitute it into the equation
0 = a(-2+3)^2 -1 to find a
0 =a(1)^2 -1
0 = a-1
1 = a
y = (x+3)^2 -1
Answer:
candice
Step-by-step explanation:
Answer: 
<u>Step-by-step explanation:</u>

f(x) = 
f(x+h) = 







The first thing to do is to get the graph. That's below. That is a very wicked looking graph. I'm not sure what happens at 0. I'm not sure it is continuous at 0. That's something to make a fuss over because x = 0 is one of the x intercepts.
y = - x^(2/5)(x(5/5) + 7).
y = - x^(2/5)(x + 7)
So one of the x intercepts is 0 and the other one is -7.
The reasons are known because the factors can be equated to 0. It does not look to me like there is exact symmetry. There is a local minimum however at what the graph says is (-2,-6.5 or so)
You could differentiate that to find the exact point, but you are not asked for that.
So the domain is from -∞ to zero and 0 to plus ∞ I think you have to exclude 0 even though it is an x intercept.
The graph decreases from -∞ < x < -2
It increases from -2 < x < 0
It decreases form 0< x < ∞
Answer:
A. X~+3.46
Step-by-step explanation:
I calculated logically