Two difference between thrust and upthrust .
1 answer:
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Complete Question
Red blood cells can be modeled as spheres of 6.53 μm diameter with −2.55×10−12 C excess charge uniformly distributed over the surface. Find the electric field at the following locations, with radially outward defined as the positive direction and radially inward defined as the negative direction. The permittivity of free space ????0 is 8.85×10−12 C/(V⋅m). What is the electric field
E⃗ 1 inside the cell at a distance of 3.05 μm from the center?
E⃗ 2 Just inside the surface of the cell
E⃗ 3 Just outside the surface of the cell
E⃗ 4 At a point outside the cell 3.05 μm from the surface
Answer:
E⃗ 1
0 V/m
E⃗ 2
0 V/m
E⃗ 3
E⃗ 4
Explanation:
From the question we are told that
The diameter is
The charge is
The permittivity of free space is
The distance considered is
Generally the electric field inside the cell at a distance of 3.05 μm from the center is
0 V/m
This because there is no electric field felt inside the cell according Gauss the cell is taken as a point charge
Generally the electric field just inside the surface of the cell is 0 V/m
This because there is no electric field felt inside the cell according Gauss the cell is taken as a point charge
Generally the electric field just outside the cell is mathematically represented as
Here is the coulomb constant with value
r is the radius of the sphere which is mathematically as
Generally the electric field at a point outside the cell 3.05 μm from the surface is mathematically represented as
Here R is mathematically represented as
=>
So
Answer:
The initial velocity of the snowball was 22.21 m/s
Explanation:
Since the collision is inelastic, only momentum is conserved. And since the snowball and the box move together after the collision, they have the same final velocity.
Let be the mass of the ball, and
be its initial velocity; let
be the mass of the box, and
be its velocity; let
be the final velocity after the collision, then according to the law of conservation of momentum:
.
From this we solve for , the initial velocity of the snowball:
now we plug in the numerical values ,
,
, and
to get:
The initial velocity of the snowball is 22.21 m/s.
<em>P.S: we did not take vectors into account because everything is moving in one direction—towards the west.</em>