Answer:
a) 2.7s
b) 29 m/s
Explanation:
The equation for the velocity and position of a free fall are the following
-(1)
- (2)
Since the hot-air ballon is <em>descending </em>at 2.1m/s and the camera is dropped at 42 m above the ground:
To calculate the time which it takes to reach the ground we use eq(2) with x=0, and look for the positive solution of t:
t = 2.71996
Rounding to two significant figures:
t = 2.7 s
Now we calculate the velocity the camera had just before it lands using eq(1) with t=2.7s
v = -28.782 m/s
Rounding to two significant figures:
v = -29 m/s
where the minus sign indicates the downwards direction
The entropy change<span> of the surroundings is driven by heat flow and the heat flow determines the sign of ΔS</span>surr<span>. It can be calculated by the following expression:
</span>ΔSsurr = -(ΔH) / T
We calculate as follows:
ΔSsurr = -13200 / 1337 = 9.87 J/ K mol
Hope this answers the question. Have a nice day.
Answer:
Correct option : (c) period.
Explanation:
The time that is required for a vibrating object to complete one full cycle is called the time period. If f is the frequency of a wave, then the relation between the frequency and the time period is given by :
These are the characteristics of a wave. Some other characteristics are wavelength, amplitude, intensity etc. So, the correct option is (c) "period".
Answer:
180^2 + 390^2 = force ^2 (Pythagoras) root of force^2 = 429.5N approx resultant force Acceleration = Force/Mass 429.5/270 = 1.5907 ms^-2 in a Southwesterly direction.
Explanation:
