Answer:
CH₃CH(CH₃)CH(C₃H₇)CH₂CH(CH₃)₂:
4-isopropyl-2-methylpentane.
Explanation:
Step One: Draw the structure formula of this compound. Parentheses in the formula indicate substitute groups that are connected to the carbon atom to the left.
For example, the first (CH₃) indicates that the second carbon atom from the left is connected to:
- the CH₃- on the left-hand side,
- the -CH(C₃H₇)CH₂CH(CH₃)₂ on the right-hand side,
- a hydrogen atom, and
- an additional CH₃- group that replaced one hydrogen atom.
Each carbon atom in this compound is connected to four other atoms. All bonds between carbon atoms are single bonds.
The C₃H₇ in the second pair of parentheses is the condensed form of CH₃CH₂CH₂-. See the first sketch attached. Groups in parentheses are highlighted.
Step Two: Find the carbon backbone. The backbone of a hydrocarbon is the longest chain of carbon atoms that runs through the compound. See the second sketch attached. The backbone of this compound consists of seven carbon atoms and is highlighted in green. The name for this backbone shall be heptane.
Step Three: Identify and name the substitute groups.
The two substitute groups are circled in blue in the second sketch.
- The one on the right -CH₃ is a methyl group.
- The one on the left is branched.
![\begin{aligned}\text{CH}_3-&\text{CH}-\text{CH}_3\\[-0.5em]&\;|\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Ctext%7BCH%7D_3-%26%5Ctext%7BCH%7D-%5Ctext%7BCH%7D_3%5C%5C%5B-0.5em%5D%26%5C%3B%7C%5Cend%7Baligned%7D)
This group can be formed by removing one hydrogen from the central carbon atom in propane. The name for this group is isopropyl.
Step Four: Number the atoms.
Isopropyl shall be placed before methyl. Start from the right end to minimize the index number on all substitute groups. The methyl group is on carbon number two and the isopropyl group on carbon number four. Hence the name:
4-isopropyl-2-methylheptane.
Answer: The molar solubility of barium fluoride is 0.0183 moles/liter.
Explanation:
The equation for the reaction will be as follows:
By Stoichiometry,
1 mole of 
gives 2 moles of 
and 1 mole of 
Thus if solubility of is s moles/liter, solubility of is s moles/liter and solubility of is 2s moles/liter
Therefore,
![K_sp=[Ba^{2+}][F^{-}]^2](https://tex.z-dn.net/?f=K_sp%3D%5BBa%5E%7B2%2B%7D%5D%5BF%5E%7B-%7D%5D%5E2)
![2.45\times 10^{-5}=[s][2s]^2](https://tex.z-dn.net/?f=2.45%5Ctimes%2010%5E%7B-5%7D%3D%5Bs%5D%5B2s%5D%5E2)
Thus the molar solubility of barium fluoride is 0.0183 moles/liter.
Given ,
Mass of sample of cobalt = 27 g
density of sample of cobalt = 9g/cm^3
We know that ,
Density = mass of sample/volume of sample
From that relation ,
We can deduce the following as
Volume = mass of sample/density of sample
Hence , required volume of sample of cobalt = 27 g /9 g/cm^3 = 3 cm^3
The volume is
This liquid is sometimes colored alcohol but can also be a metallic liquid called mercury. Both mercury and alcohol grow bigger when heated and smaller when cooled. Inside the glass tube of a thermometer, the liquid has no place to go but up when the temperature is hot and down when the temperature is cold. Mercury is very reactive and works best. But mercury is also very a radioactive element. So, if you break the thermometer, you could get in trouble (radio active posoning) Alcohol work well, it is not radioactive and can't kill you.
Okay, hope I helped
:)))
Answer:
10.8 g
Explanation:
<em>A chemist adds 480.0 mL of a 0.169 mol/L aluminum chloride solution to a reaction flask. Calculate the mass in grams of aluminum chloride the chemist has added to the flask. Round your answer to 3 significant digits.</em>
Step 1: Given data
- Volume of the solution: 480.0 mL
- Concentration of the aluminum chloride solution: 0.169 mol/L
Step 2: Calculate the moles of aluminum chloride in the solution
We will multiply the volume of the solution by the molarity.
0.4800 L × 0.169 mol/L = 0.0811 mol
Step 3: Calculate the mass corresponding to 0.0811 moles of AlCl₃
The molar mass of AlCl₃ is 133.34 g/mol.
0.0811 mol × 133.34 g/mol = 10.8 g
