Convection currents cause the magma under the trench to slowly rise causing the trench to open up further releasing this magma at the same time.
Answer:
Explanation:
Decomposers is the correct answer
Answer:
the 2kg ball
Explanation:
there is less mass to move so the 2kg ball will move faster. the kinetic energy of the 5kg ball will move slower due to the fact that it needs more energy to move if it has more mass.
Answer:
Neither.
Explanation:
After 10 seconds the object will have travelled 490.5m, not 98.1. The vertical distance covered in freefall by an object in time t is given by Distance= 1/2 x 9.81 x t^2. Simply multiplying 9.81 by the time will NOT give the distance covered.
The acceleration of the object will not change, it will always be 9.81 m/s^2. Its speed will keep increasing by 9.81 m/s every second, thats what the ‘per second squared*’ means. The speed after 10 seconds will be 98.1 m/s
To summarise, after 10 seconds, the object will have covered 490.5 metres, and it will have a final speed of 98.1 m/s. It’s acceleration will remain 9.81 m/s^2 at all times
Answer:
The velocity component in south direction is 42.42 miles/hour and in west direction is 42.42 miles/hour.
Explanation:
Given that,
Speed = 60 miles/hour
Direction = south west
Let the south in y axis and west in x axis.
Angle between x and y will be θ.
The component of speed is
of x axis and
of y axis.
![\vect{V}=\vec{V_{x}i}+\vec{V_{y}j}](https://tex.z-dn.net/?f=%5Cvect%7BV%7D%3D%5Cvec%7BV_%7Bx%7Di%7D%2B%5Cvec%7BV_%7By%7Dj%7D)
Where,
...(I)
....(II)
We know that,
The south west direction makes 45° with west direction in x axis.
(a). We need to calculate the velocity component in south direction
Using equation (I)
![V_{x}=|\vec{V}|\cos\theta](https://tex.z-dn.net/?f=V_%7Bx%7D%3D%7C%5Cvec%7BV%7D%7C%5Ccos%5Ctheta)
Put the value into the formula
![V_{x}=60\times\cos45](https://tex.z-dn.net/?f=V_%7Bx%7D%3D60%5Ctimes%5Ccos45)
![V_{x}=42.42\ miles/hour](https://tex.z-dn.net/?f=V_%7Bx%7D%3D42.42%5C%20miles%2Fhour)
(b). We need to calculate the velocity component in west direction
Using equation (II)
![V_{x}=|\vec{V}|\sin\theta](https://tex.z-dn.net/?f=V_%7Bx%7D%3D%7C%5Cvec%7BV%7D%7C%5Csin%5Ctheta)
Put the value into the formula
![V_{x}=60\times\sin45](https://tex.z-dn.net/?f=V_%7Bx%7D%3D60%5Ctimes%5Csin45)
![V_{x}=42.42\ miles/hour](https://tex.z-dn.net/?f=V_%7Bx%7D%3D42.42%5C%20miles%2Fhour)
Hence, The velocity component in south direction is 42.42 miles/hour and in west direction is 42.42 miles/hour.