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N76 [4]
2 years ago
11

Can someone help me solve this? Thanks!

Chemistry
1 answer:
IrinaVladis [17]2 years ago
5 0

Answer:

yea

Explanation:

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Write the electron configuration for a sodium cation with a charge of 1+
Dafna1 [17]

1{s}^{2} 2 {s}^{2} 2 {p}^{6}

or simply 2,8 it is isoelectronic with argon

4 0
3 years ago
Please help me out i don’t get this. what is the answers to 1-4.
VLD [36.1K]

Answer:

1. A circuit is a path that electricity flows along. It starts at a power source, like a battery, and flows through a wire to a light bulb or other object and back to other side of the power source.

2. A series circuit is one that has more than one resistor, but only one path through which the electricity (electrons) flows. All the components in a series circuit are connected end-to-end. A resistor in a circuit is anything that uses some of the power from the cell.

3. A parallel circuit is a circuit in which the electric current passes through two or more branches or connected parts at the same time before it combines again. Compare.

4. BOTH - 1. lightbulb 2. battery 3. switch

   SERIES- 1. Ammeter 2. voltmeter

i'm not sure about the rest sorry :(

7 0
3 years ago
HELP PLZ ASAP<br> will give brainliest
horrorfan [7]

Answer:

I believe that it would be the third option down.

Explanation:

The thermal energy is in constant motion in the COOLER room, and when the desired temperature in the room is reached, it stops.

8 0
3 years ago
What is the molarity of a solution that contains 40. grams of NaOH in 0.50 liter of solution
statuscvo [17]

Answer:

The molarity of the solution is: 2 M

Explanation:

We calculate the weight of 1 mol of NaOH:

Weight 1 mol NaOH= Weight Na + Weight 0 + Weight H= 23 g+16g+ 1 g= 40g/mol

The molarity is the quantity of moles in 1000ml (1 liter) of solution:

0,5liter-----40 grams NaOH

1 liter----x=(1 liter x 40 grams NOH)/0,5 liter = 80 grams NaOH

40 grams----1 mol NaOH

80 grams----X=(80 grams x 1 mol NaOH)/40 grams= 2 mol NaOH--> 2M

5 0
3 years ago
someone please explain how to separate copper powder from a mixture containing copper and zinc powder !!
jarptica [38.1K]

Answer:

by burning the mixture in an electrical furnace to a temp. 640 degree C. to melt both Zinc & Aluminum leaving copper oxide as a powder.

Explanation:

6 0
3 years ago
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