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natulia [17]
3 years ago
15

Determine if the two figures are congruent and explain your answer using transformations.

Mathematics
1 answer:
Vinvika [58]3 years ago
4 0

Answer:

Step-by-step explanation:

By observation we see that the sides:

DC = HG

CB = GF

BA = FE and DA = HE so the 2 figures are congruent.

If we reflect EFGH in the y-axis we see that the point F (4, 1( moves to (-4,1)

and the point E moves from (2, 0) o (-2, 0) and the other 2 points points move in a similar fashion.

If we then  move the whole figure up 1 unit then 1 to the right EFGH completely occupies the same area as ABCD confirming they are congruent.

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What is the answer for the question?
Dafna1 [17]
6a + 3b for a = 7 and b = 11
6(7) + 3(11)
42 + 33
75
hope this helps
4 0
3 years ago
Write 45 as a product of the gcf and another number
Maru [420]
The answer might be 45 x 1, because 45 is the greatest factor of 45.
 If you want to know why tell me
8 0
3 years ago
What is the answer to <br> 6x&gt; -54
Anestetic [448]

Answer:

6 times whatever x is would be greater that -54

7 0
3 years ago
A square has a side length of 2.5 meters. What is the largest radius of the largest that can fit inside the square.
Oksanka [162]

The largest radius of the circle that can fit inside the given square is 1.25 meters

Step-by-step explanation:

Step 1 :

Given,

the side of the square  = 2.5 meters

We need to determine the largest radius of the circle that can fit inside this square

Step 2 :

The diameter of the largest circle that can fit inside a square will be equal to length of given square's side.

So here the largest diameter will be 2.5 meters

Therefore the radius  = diameter ÷ 2 = 2.5 ÷ 2 = 1.25 meters

Step 3 :

Answer :

The largest radius of the circle that can fit inside the given square is 1.25 meters

6 0
3 years ago
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle:
In-s [12.5K]

\huge\boxed{11\ \text{units}}

To solve this, we need to find the distance between points C and D.

The distance formula is:

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the values from points C(x_1, y_1) and D(x_2, y_2).

\sqrt{(-4-(-4))^2+(-5-6)^2}

Subtract.

\sqrt{0^2+(-11)^2}

Evaluate the powers.

\sqrt{0+121}

Solve for the final answer.

\sqrt{121}\\\boxed{11}

8 0
2 years ago
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