Calculate Δ = b^2 -4ac => Δ = 169 => k1 = 3/2; k2 = -5 => 2k^2 + 7k - 15 = 2*(k -3/2)(k+5) = (2k - 3)(k+5);
Answer:
Step-by-step explanation:
Vertex form is accomplished by completing the square on the quadratic. Do this by first setting the parabola equal to 0 then moving the constant over to the other side:

Now take half the linear term, square it, and add it to both sides. Our linear term is 6. Half of 6 is 3, and 3 squared is 9:

The reason we do this is to create a perfect square binomial on the left:
(obviously the 0 results from the addition of 9 and -9). Move the 0 back over to the other side and set the quadratic back equal to y:

This gives you a vertex of (-3, 0), which is a minimum value, since the parabola opens upwards.
Divide numerator (top number) by denominator (bottom number). 3 divided by 8. It’s 0.375
La respuesta correcta el la letra D
Answer:
12 x 4/3 = 16........(total) so...
1 represent 1/16