Question

The PTA sells 100 tickets for a raffle and puts them in a bowl. They will randomly pull out a ticket for the first prize and then another ticket for the second prize. You have 10 tickets and your friend has 10 tickets. What is the probability that your friend wins the first prize and you win the second prize?

Answer 1

0.0101 = 1.01% probability that your friend wins the first prize and you win the second prize.

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A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

Event A: Your friend wins the first prize.

Event B: You win the second prize.

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Probability friend wins first prize:

10 out of 100 tickets, so:

$P(A) = \frac{10}{100}$

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Probability you win second prize:

There will be 99 tickets remaining(1 has been sorted), you have then of then, so:

$P(B) = \frac{10}{99}$

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What is the probability that your friend wins the first prize and you win the second prize?

Multiplication of the probabilities, thus:

$p = P(A) \times P(B) = \frac{10}{100} \times \frac{10}{99} = \frac{10\times10}{100\times99} = 0.0101$

0.0101 = 1.01% probability that your friend wins the first prize and you win the second prize.

A similar question is given at brainly.com/question/22281693