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Cloud [144]
2 years ago
6

The U.S. swim team won 13 gold medals in a recent competition against two other countries.Of the total 60 medals awarded, there

were 20 each of bronze, silver, and gold. Spain won 5gold medals. France won one-third of all the medals and had an equal number of silver andbronze medals. How many silver and bronze medals did France win?
Mathematics
1 answer:
Kitty [74]2 years ago
3 0

The number of silver and bronze medals that France won are 9 silver and bronze medals.

Since there are 60 medals awarded, and there were 20 each of bronze, silver, and gold. This means that there are 20 gold, 20 bronze and 20 silver.

Since U.S. swim team won 13 gold medals and Spain won 5gold medals, then the gold won by France will be:

= 20 - (13 + 5)

= 20 - 18

= 2 gold medals

France won 2 gold medals.

Since France won one-third of all the medals, the number of medals won by France will be:

= 1/3 × 60

= 20 medals

Since France won 2 golds medals, then the number of silver and bronze will be:

= 20 - 2

= 18 silver and bronze medals.

Since France won equal number of silver and bronze medals. This will be:

= 18/2

= 9 silver and bronze medals.

Read related link on:

brainly.com/question/19972449

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first look at all the numbers in the relation.then since inverse means opposite find the answers where the numbers in the parenthesis are in the opposite order than the question. Finally look for the answer In which all the positive numbers in the parenthesis(in the given relation) are negative (on the answers)and the negative numbers (in the given relation) are positive (on the answers).

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34 minutes

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Given

Time\ Spent = 6

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What is the image of the point (8,-6) after a rotation of 180° counterclockwise
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3 years ago
Suppose parts (a) through (d) below provide results for a study on the role of calcium in reducing the symptoms of PMS. For each
frutty [35]

Answer:

Step-by-step explanation:

Hello!

To test if calcium reduces the symptoms of PMS two independent groups of individuals are compared, the first group, control, is treated with the placebo, and the second group is treated with calcium.

The parameter to be estimated is the difference between the mean symptom scores of the placebo and calcium groups, symbolically: μ₁ - μ₂

There is no information about the distribution of both populations X₁~? and X₂~? but since both samples are big enough, n₁= 228 and n₂= 212, you can apply the central limit theorem and approximate the sampling distribution to normal X[bar]₁≈N(μ₁;δ₁²/n) and X[bar]₂≈N(μ₂;δ₂²/n)

The formula for the CI is:

[(X[bar]₁-X[bar]₂) ± Z_{1-\alpha /2} * \sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} }]

95% confidence level Z_{1-\alpha /2}= Z_{0.975}= 1.96

(a) mood swings: placebo = 0.70 ± 0.78; calcium = 0.50 ± 0.53

X₁: Mood swings score of a participant of the placebo group.

X₂: Mood swings score of a participant of the calcium group.

[(0.70-0.50) ± 1.96 * \sqrt{\frac{0.78^2}{228} +\frac{0.53^2}{212} }]

[0.076; 0.324]

(b) crying spells: placebo = 0.39 + 0.57; calcium = 0.21 + 0.40

X₁: Crying spells score of a participant of the placebo group.

X₂: Crying spells score of a participant of the calcium group.

[(0.39-0.21) ± 1.96 * \sqrt{\frac{0.57^2}{228} +\frac{0.40^2}{212} }]

[0.088; 0.272]

(c) aches and pains: placebo = 0.45 + 0.60; calcium = 0.37 + 0.45

X₁: Aches and pains score of a participant of the placebo group.

X₂: Aches and pains score of a participant of the calcium group.

[(0.45-0.37) ± 1.96 * \sqrt{\frac{0.60^2}{228} +\frac{0.45^2}{212} }]

[-0.019; 0.179]

(d) craving sweets or salts: placebo = 0.60 + 0.75; calcium = 0.44 + 0.61

X₁: Craving for sweets or salts score of a participant of the placebo group.

X₂: Craving for sweets or salts score of a participant of the calcium group.

[(0.60-0.44) ± 1.96 * \sqrt{\frac{0.75^2}{228} +\frac{0.61^2}{212} }]

[0.032; 0.287]

I hope this helps!

6 0
3 years ago
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