Answer:
Step-by-step explanation:
Domain x^2 - 9 {Solution: - infinity < x < infinity}
Interval notation (- infinity, infinity)
Range of x^2 - 9 (Solution: f(x) is greater than or equal to - 9)
Interval notation (-9, infinity)
Axis interception points of x^2 - 9:
X- intercepts (3, 0) (-3, 0)
Y-intercepts (0, -9)
Vertex of x^2 - 9: Minimum (0, -9)
Solve for f:
f (x) = x^2 - 9
Step 1: Divide both sides by x.
fx / x = x^2 - 9 / x
f = x^2 - 9 / x
Answer:
f = x^2 - 9 / x
Answer:
Ayush's route is 0.7 km or 700m longer than Sumit route.
Step-by-step explanation:
Ayush's route is 1km 2hm long while sumit route is 2hm 30dam.
We know that,
1 km = 10 hm
1 dam = 0.1 hm
Using these conversions we get
Ayush's route = 1km 2hm = (1×10) hm + 2 hm = 12 hm
Sumit route = 2hm 30dam = 2 hm + (30×0.1) hm = 2 hm + 3 hm = 5 hm
Ayush's route is longer.
Difference = 12 hm - 5 hm = 7 hm = 0.7 km [1 km = 10 hm]
Hence, Ayush's route is 0.7 km or 700 m longer than Sumit route.
Answer:
F. 8
Step-by-step explanation:
The ratio of the long side to the short side is the same in similar triangles. The long side of triangle BAD is AD, which has length 20-4 = 16.
BD/DE = AD/BD
h/4 = 16/h
h^2 = 64 . . . . . . . multiply by 4h
h = 8 . . . . . . . . . . take the square root (matches selection F)
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<em>Comment on this geometry</em>
BD = √(AD·DC) is called the "geometric mean" of the segments AD and DC. This geometry has some other geometric mean relationships as well:
BC = √(AC·DC)
BA = √(AC·AD)
Answer:
do you have a picture of this
The answer to that question is (5x+3).
