Answer:
gamma ray
Explanation:
Gamma emission results in the release of energy without any apparent change in mass or nuclear charge.
Properties of Gamma radiations:
Gamma radiations are high energy radiations having no mass.
These radiations are travel at the speed of light.
Gamma radiations can penetrate into the many materials.
These radiations are also used to treat the cancer.
Lead is used for the protection against gamma radiations because of its high molecular density.
The lead apron are used by the person when treated with gamma radiations.
Lead shields are also used in the wall, windows and doors of the room where gamma radiations are treated, in-order to protect the surroundings.
<u>Answer:</u> The volume of the gas is 178.76 L
<u>Explanation:</u>
The ideal gas equation is given as:
.......(1)
where
P = pressure of the gas = 675 torr
V = volume of gas = ?
n = number of moles of gas = 6.45 moles
R = Gas constant = 62.36 L.torr/mol.K
T = temperature of the gas = ![27^oC=[27+273]K=300K](https://tex.z-dn.net/?f=27%5EoC%3D%5B27%2B273%5DK%3D300K)
Putting values in equation 1, we get:

Hence, the volume of the gas is 178.76 L
Answer : The fugacity in the solution is, 16 bar.
Explanation : Given,
Fugacity of a pure component = 40 bar
Mole fraction of component = 0.4
Lewis-Randall rule : It states that in an ideal solution, the fugacity of a component is directly proportional to the mole fraction of the component in the solution.
Now we have to calculate the fugacity in the solution.
Formula used :

where,
= fugacity in the solution
= fugacity of a pure component
= mole fraction of component
Now put all the give values in the above formula, we get:


Therefore, the fugacity in the solution is, 16 bar.
Answer:
See explanation
Explanation:
Given Einstein's theory of relativity, we have that;
E= mc^2
m= mass of the substance
c= speed of light
For one gram of the substance,
E= 1 ×10^-3 × (3 × 10^8)^2
E = 9 × 10^13 J
For 8.7 g of matter;
E = 8.7 × 10^-3× (3 × 10^8)
E= 7.83 ×10^ 14 J