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Digiron [165]
2 years ago
6

What is pH of a solution where [H+]=0.000044 M

Chemistry
1 answer:
enot [183]2 years ago
8 0

Answer:

<em><u>pH = 4.36</u></em>

Explanation:

<em>F</em><em>r</em><em>o</em><em>m</em><em> </em><em>d</em><em>e</em><em>f</em><em>i</em><em>n</em><em>i</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>p</em><em>o</em><em>t</em><em>e</em><em>n</em><em>z</em><em> </em><em>h</em><em>y</em><em>d</em><em>r</em><em>o</em><em>g</em><em>e</em><em>n</em><em>,</em>

<em>p</em><em>H</em><em> </em><em>=</em><em> </em><em>-</em><em>l</em><em>o</em><em>g</em><em>[H+]</em>

<em>p</em><em>H</em><em> </em><em>=</em><em> </em><em>-</em><em>l</em><em>o</em><em>g</em><em>(</em><em>0.000044</em><em>)</em>

<em>p</em><em>H</em><em> </em><em>=</em><em> </em><em>4</em><em>.</em><em>3</em><em>6</em>

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Sveta_85 [38]

Answer:

gamma ray

Explanation:

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3 0
3 years ago
Find the volume of 6.45 moles of gas present at a temperature of 27.0oC and a pressure of 675 torr.
maw [93]

<u>Answer:</u> The volume of the gas is 178.76 L

<u>Explanation:</u>

The ideal gas equation is given as:

.......(1)

where

P = pressure of the gas = 675 torr

V = volume of gas = ?

n = number of moles of gas = 6.45 moles

R = Gas constant = 62.36 L.torr/mol.K

T = temperature of the gas = 27^oC=[27+273]K=300K

Putting values in equation 1, we get:

675torr\times V=6.45mol\times 62.36L.torr/mol.K\times 300K\\\\V=\frac{6.45\times 62.36\times 300}{675}=178.76 L

Hence, the volume of the gas is 178.76 L

3 0
3 years ago
What is the concentration of a solution in which 60 g of NaCl are dissolved in 1.0 L of water?
Dima020 [189]
What am I answering????
7 0
3 years ago
If the fugacity of a pure component at the conditions of an ideal solution is 40 bar and its mole fraction is 0.4, what is its f
yaroslaw [1]

Answer : The fugacity in the solution is, 16 bar.

Explanation : Given,

Fugacity of a pure component = 40 bar

Mole fraction of component  = 0.4

Lewis-Randall rule : It states that in an ideal solution, the fugacity of a component is directly proportional to the mole fraction of the component in the solution.

Now we have to calculate the fugacity in the solution.

Formula used :

f_i=X_i\times f_i^o

where,

f_i = fugacity in the solution

f_i^o = fugacity of a pure component

X_1 = mole fraction of component

Now put all the give values in the above formula, we get:

f_i=0.4\times 40\text{ bar}

f_i=16\text{ bar}

Therefore, the fugacity in the solution is, 16 bar.

4 0
3 years ago
When the plutonium bomb was tested in New Mexico in 1945, approximately 1 gram of matter was converted into energy. Suppose anot
stiv31 [10]

Answer:

See explanation

Explanation:

Given Einstein's theory of relativity, we have that;

E= mc^2

m= mass of the substance

c= speed of light

For one gram of the substance,

E= 1 ×10^-3 × (3 × 10^8)^2

E = 9 × 10^13 J

For 8.7 g of matter;

E = 8.7 × 10^-3× (3 × 10^8)

E= 7.83 ×10^ 14 J

6 0
3 years ago
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