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Digiron [165]
3 years ago
6

What is pH of a solution where [H+]=0.000044 M

Chemistry
1 answer:
enot [183]3 years ago
8 0

Answer:

<em><u>pH = 4.36</u></em>

Explanation:

<em>F</em><em>r</em><em>o</em><em>m</em><em> </em><em>d</em><em>e</em><em>f</em><em>i</em><em>n</em><em>i</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>p</em><em>o</em><em>t</em><em>e</em><em>n</em><em>z</em><em> </em><em>h</em><em>y</em><em>d</em><em>r</em><em>o</em><em>g</em><em>e</em><em>n</em><em>,</em>

<em>p</em><em>H</em><em> </em><em>=</em><em> </em><em>-</em><em>l</em><em>o</em><em>g</em><em>[H+]</em>

<em>p</em><em>H</em><em> </em><em>=</em><em> </em><em>-</em><em>l</em><em>o</em><em>g</em><em>(</em><em>0.000044</em><em>)</em>

<em>p</em><em>H</em><em> </em><em>=</em><em> </em><em>4</em><em>.</em><em>3</em><em>6</em>

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storchak [24]

Answer:

<h2>252.9 kPa</h2>

Explanation:

The new pressure can be found by using the formula

P_2 =  \frac{P_1V_1}{V_2}  \\

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

From the question we have

P_2 =  \frac{300 \times 295}{350}  \\  = 252.85714

We have the final answer as

<h3>252.9 kPa</h3>

Hope this helps you

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Reason:

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If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit 


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