Answer:

Explanation:
A right triangle is formed, in which the vertical elevation is the opposite cathetus and the horizontal distance is the adjacent cathetus, since we know these two values, we can calculate the angle of inclination using the definition of tangent:

Starting velocity (u)=0
acceleration (a) = 9.8
time (t) = 1.5
final velocity (v) =?
v=at+u
v=9.8(1.5)+0
v=14.7m/s2
After one day, the rate of increase in Delta Cephei's brightness is;0.46
We are informed that the function has been used to model the brightness of the star known as Delta Cephei at time t, where t is expressed in days;
B(t)=4.0+3.5 sin(2πt/5.4)
Simply said, in order to determine the rate of increase, we must determine the derivative of the function that provides
B'(t)=(2π/5.4)×0.35 cos(2πt/5.4)
Currently, at t = 1, we have;
B'(1)=(2π/5.4)×0.35 cos(2π*1/5.4)
Now that the angle in the bracket is expressed in radians, we can use a radians calculator to determine its cosine, giving us the following results:
B'(1)=(2π/5.4)×0.3961
B'(1)≈0.46
To know more about:
brainly.com/question/17110089
#SPJ4
<span> 50 J
</span>Ke = 0.5 * m * v^2 ( m = mass(Kg), V = Velocity(m/s)
<span>= 0.5 * 4 * 5^2 </span>
<span>= 2 * 25 </span>
<span>= 50 J </span>