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valentinak56 [21]
3 years ago
15

Adding the fractions 3/14+2/21+1/6

Mathematics
1 answer:
NARA [144]3 years ago
6 0

Answer:

\frac{10}{21}

Step-by-step explanation:

The LCM of 14, 21 and 6 is 42

We require to change the fractions to fractions with a denominator of 42

\frac{3(3)}{14(3)} + \frac{2(2)}{21(2)} + \frac{1(7)}{6(7)}

= \frac{9}{42} + \frac{4}{42} + \frac{7}{42} ← add the numerators, leaving the denominator

= \frac{9+4+7}{42}

= \frac{20}{42} ← divide both values by 2

= \frac{10}{21} ← in simplest form

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4x+11y=7<br><br>4x+3y=-1<br>what are the steps
andreev551 [17]

Answer:

x = -1, y = 1

Step-by-step explanation:

Given that:

\begin{bmatrix}4x+11y=7\\ 4x+3y=-1\end{bmatrix}

Isolate x for 4x + 11y = 7 which ⇒ x=\frac{7-11y}{4}

Substitute x=\frac{7-11y}{4} into the equation: which is:

\begin{bmatrix}4\cdot \frac{7-11y}{4}+3y=-1\end{bmatrix}

Drop Down to:

\begin{bmatrix}7-8y=-1\end{bmatrix}

Isolate y for 7-8y = -1: y = 1

Thus, x=\frac{7-11y}{4}

Substitute y = 1

Hence,

x=\frac{7-11\cdot \:1}{4}=-1

Solution ⇒ x = -1 and y = 1

<u><em>~learn with lenvy~</em></u>

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2 years ago
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jeka94

Answer:

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Step-by-step explanation:

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3 years ago
Find Distance (4,6) (-4,-3)​
vampirchik [111]

Answer:

\sqrt{145}

Step-by-step explanation:

The distance formula states that the distance between two points (a,b) and (c,d) is \sqrt{(a-c)^2+(b-d)^2}.

The two points we have are (4,6) and (-4,-3). Plugging these numbers into the distance formula, we have

\sqrt{(4-(-4))^2+(6-(-3))^2.

Simplifying with order of operations, first using the distributive property, gives

\sqrt{(4+4)^2+(6+3)^2.

Squaring and adding gives

\sqrt{(4+4)^2+(6+3)^2}=\sqrt{8^2+9^2}\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~=\sqrt{64+81}\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~=\boxed{\sqrt{145}},

which is the answer in simplest form. This also rounds to about 12.04.

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2 years ago
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The answer would be A
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