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Alexxandr [17]
3 years ago
6

Given: T is the midpoint of JK¯¯¯¯¯JK¯, JK = 5x – 3, and JT = 2x + 1. Determine the length of JK¯¯¯¯¯JK¯

Mathematics
2 answers:
nikitadnepr [17]3 years ago
7 0

Answer:

SO your just kidding alot

Step-by-step explanation:

Helen [10]3 years ago
6 0
JK where T is the midpoint.   J >>>>> T >>>>> K. 

JK = 5x - 3
JT = 2x + 1

Because T is the midpoint, it means that  JT = TK
So, JT + TK = JK

(2x + 1) + (2x + 1) = 5x - 3
4x + 2 = 5x - 3
4x - 5x = -3 - 2
-x = -5
x = 5

JK = 5x - 3
JK = 5(5) - 3
JK = 25 -3
JK = 22

The length of JK is 22.
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Zinaida [17]
The slope-intercept form is written under the form of
y=mx+b where m represent the slope and y represent y-intercept. In this case, we know that the m is 8, but we don't have b yet. To find the answer, substitute (0,5) into an equation where y=5 and x=0
y=mx+b
y=8x+b
5=8(0)+b
5=b, so we have the complete y-intercept form which is y=8x+b
Or
You can you this
y-y1=m(x-x1) where point (x1,y1) represent point (0,5) in this case which led to:
y-y1=m(x-x1)
y-5=8(x-0)
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Add 5 to each side
y-5+5=8x+5
y=8x+5 represent the slope-intercept form. Hope it help!
4 0
3 years ago
Find 3 ordered pairs for each equation <br><br> Y= 5x+1 <br><br> Y=10 - x <br><br> Y= 2x
tangare [24]
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2. (0,10) , (1,9) , (2,8)

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5 0
2 years ago
Help! How would I solve this trig identity?
NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}

Then the identity can be rewritten as:

sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}  = \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)} \\\\

Now we can multiply both sides by cos⁴(x) to get:

\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}  = \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)

Now we can use the identity:

sin²(x) + cos²(x) = 1

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Thus, the identity was proven.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

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7 0
1 year ago
Carnival M charges an entrance fee of $5.00 and $0.65 per ticket for the rides. Carnival P
MA_775_DIABLO [31]
25 tickets

I put the information into this equation 5+0.65x=10+0.45x

I solved the equation by first subtracting the 0.45x from both sides to get the variable on one side. I was left with 5+0.20x=10. Then I subtracted the 5 from both sides and got 0.20x=5. Finally I divided both sides by 0.20 to get the X by itself and got X=25
3 0
3 years ago
A region with a 10-mile radius has a population density of about 1500 people per square mile. Find the number of people who live
riadik2000 [5.3K]

The total population in the region is 942000

<u>Step-by-step explanation:</u>

Radius of the region= 10 miles

Population density= 1500 per square mile

Area of the region = 2π(r x r)

= 2π(10 x 10)

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= 628 square miles

Population = 1500 x 628

= 942000

The total population in the region is 942000

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3 years ago
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