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Sedaia [141]
2 years ago
8

Round the number to the given place value. 47,709,982; millions

Mathematics
1 answer:
Rudiy272 years ago
6 0

Answer:

48,000,000

Step-by-step explanation:

47,709,982

Look at the millions place and then see if the number after that is a greater number than 4. If it isn't, round down but if it is, round up

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Which explicit formula describes the sequence<br><br>use the picture for the full question​
Murrr4er [49]

Answer:

  • A. aₙ = (2/7)ⁿ⁻¹

Step-by-step explanation:

<u>According to sequence we observe:</u>

  • the first term is a₁ = 1
  • the common ratio is r = 2/7

<u>Equation of nth term of GP:</u>

  • aₙ = a₁r°⁻¹

<u>Substitute to get:</u>

  • aₙ = 1*(2/7)ⁿ⁻¹ = (2/7)ⁿ⁻¹

Correct choice is A

7 0
2 years ago
Margie is practicing for an upcoming tennis tournament. Her first serve is good 20 out of 30 times on average. Margie wants to k
mojhsa [17]

Answer:

0.6804

Step-by-step explanation:

Given that Margie is practicing for an upcoming tennis tournament. Her first serve is good 20 out of 30 times on average.

Since each trial is independent and there are two outcomes, X no of good serves is binomial with n=6 and p =2/3

Required probability

= Prob that atleast four of 6 times good serve

=P(X\geq 4)

=P(x=4,5 or 6)\\=1-F(3)\\=0.6804

Formula used:

P(X=r) =6Cr (\frac{2}{3}^r )(\frac{1}{3}^{6-r}  )

7 0
3 years ago
Read 2 more answers
Decide which chi-square test (goodness-of fit, homogeneity, or independence) would be most appropriate for the given situation.
sasho [114]

Answer:

C. Test for Goodness-of-fit.

Step-by-step explanation:

C. Test for Goodness-of-fit would be most appropriate for the given situation.

A. Test Of  Homogeneity.

The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.

B. Test for Independence.

The chi square  is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.

C. Test for Goodness-of-fit.

The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with  their estimates and provided that one degree of freedom is deducted for each parameter estimated.

4 0
2 years ago
Solve the equation. x6−7=5 The first step is to___ on both sides of the equation. The second step is to___ on both sides of the
gogolik [260]

Answer:

x=2

Step-by-step explanation:

x6−7=5

x6=7+5

x6=12|:6

x=2

3 0
3 years ago
How do i find answes to endjunity geomatry
konstantin123 [22]

Answer:

Hey there !

Under the More button, select View Course Structure.

Find the lesson to view the assessment answers. Click Quiz Answers.

All the assessment questions related to the lesson are found in the pop-up window. To view a question and answer, select a question number.

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3 years ago
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