What is the most accurate and precise method to measure the thickness of a coin?
1 answer:
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Answer:
the required frequency of waves is 2.066 Hz
Explanation:
Given the data in the question;
μ = 1.50 kg/m
T = 6000 N
Amplitude A = 0.500 m
P = 2.00 kW = 2000 W
we know that, the average power transmit through the rope can be expressed as;
p = vμω²A²
p = √(T/μ)μω²A²
so we solve for ω
ω² = 2P / √(T/μ)μA²
we substitute
ω² = 2(2000) / √(6000/1.5)(1.5)(0.500)²
ω² = 4000 / 23.71708
ω² = 168.65
(2πf)² = ω²
so
(2πf)² = 168.65
4π²f² = 168.65
f² = 168.65 / 4π²
f² = 4.27195
f = √4.27195
f = 2.066 Hz
Therefore, the required frequency of waves is 2.066 Hz
Answer:
Star X is much closer since it is at a distance 1 parsec from the Earth.
Explanation:
The angle due to the change in position of a nearby object against the background stars it is known as parallax.
The parallax angle can be used to find out the distance by means of triangulation. Making a triangle between the nearby star, the Sun and the Earth. This angle is gotten when the position of the object is measured in January and then in July according to the configuration of the Earth with respect to the Sun in those months.
The distance between the Earth and the Sun is 150000000 Km. That distance is also known as an astronomical unit (1AU).
The parallax angle can be defined in the following way:
Where d is the distance to the star.
(1)
Equation (1) can be rewritten in terms of d:
(2)
Equation (2) represents the distance in a unit known as parsec (pc).
Case of Star X (p('') = 1):
Using equation 2 the distance of star X can be known:
So, star X is at 1 parsec from Earth.
Case of Star Y ():
So, star Y is at 2 parsecs from the Earth.
Hence, star X is much closer.
Reminder:
Notice that in equation 2 the distance is inversely proportional to the parallax angle, so if the parallax angle decreases, the distance increases.
