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SIZIF [17.4K]
3 years ago
5

What is the most accurate and precise method to measure the thickness of a coin? ​

Physics
1 answer:
choli [55]3 years ago
6 0

Answer:

The most accurate and precise method to measure the thickness of a coin would be by a micrometer screw guage.

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Two Forces are exerted on an Object In a Vertical Direction: A 20N force downwards, and 10 N force upwards. The mass of the obje
SVEN [57.7K]
When you add up (20N down) and (10N up), 
you get a sum of (10N down).

The mass of the object has no effect on the forces.


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A quarterback throws a football with an initial velocity v at an angle θ above horizontal. Assume the ball leaves the quarterbac
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(a) The y-component or vertical velocity is calculated using:
Vy = Vsin(∅)

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6 0
3 years ago
39 liters of water at
Harman [31]

Answer:

Temperature of the mixture=8 °C

Explanation:

Let, Temperature of the mixture=t °C

Q₁ = Q₂

=> m₁SΔΘ₁ = m₂SΔΘ₂

=> 39 × (20+t) = 21 × (60-t)

∴ t = 8 °C

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3 0
3 years ago
Answer the following questions
zaharov [31]

Answer:

9 - 10N to the left

10 - There is no change on the object

Explanation:

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7 0
2 years ago
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Charge is placed on two conducting spheres that are very far apart and connected by a long thin wire. The radius of the smaller
mrs_skeptik [129]

Answer:

surface charge density on each sphere is 440 \times 10^{-9} C

Explanation:

given data

radius of smaller sphere = 5 cm

radius of  larger sphere is 12 cm

electric field at surface of larger sphere = 660 kV/m = 660 × 1000 v/m

solution

we apply here electric field formula that is express as

E = (\frac{1}{4\pi\epsilon  })\times  (\frac{Q_{1} }{R^{2} } )    .................1

put here value

660000 = 9 \times 10^9 \times \frac{Q1}{0.12^2}  

Q1 = 1056 × 10^{-9}

and

here field inside a conductor is zero so that electric potential ( V ) is constant

\frac{Q{1} }{R} = \frac{Q{2} }{r}   ..................2

so Q2 will be

Q2 =  \frac{5}{12} \times 1056 \times 10^{-9}  

Q2 =  440 \times 10^{-9}  C

6 0
3 years ago
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