Question

A snowball is launched horizontally from the top of a building at v = 16.9 m/s. If it lands d = 44 meters from the bottom, how high (in m) was the building?

Answer 1

$v_x=16,9\frac{m}{s}\\ s=44m\\ g=10\frac{m}{s^2}\\\\ v_x=\frac{s}{t}\Rightarrow t=\frac{s}{v_x}\\\\ t=\frac{44}{16,9}\\\\ t=2,6s\\\\ h=\frac{gt^2}{2}\\\\ h=\frac{10*2,6^2}{2}\\\\ h=5*6,76\\\\ h=33,8m$