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3 years ago

Identify the forces acting on the cars and explain why the cars do not slide down the hill

1 answer:

5 0

<span>Examples of outside forces acting on a car is gravity, wind, and other cars. Cars do not slide down hills because their weight, combined with the friction of their tires against the road, hold them in place. </span>

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The tire above has a recommended tire pressure of 35 PSI, however, its current pressure is only 26 PSI. Which of the following c

Dima020 [189]

Answer:

option B

Explanation:

It is given that in the tire the recommended pressure is 35 PSI however the current pressure is only 26 PSI which means that pressure in the tire is less than the recommended so the chances of blowout of the tire gets eliminated hence option A is not correct.

Having pressure less in the tire can lead to the Unstable handling of the vehicle.

so correct answer is option B

7 0

3 years ago

Please answer above in the picture thanks

Vera_Pavlovna [14]

Answer:1.14.102 on the side of 10

Explanation:

6 0

3 years ago

A certain freely falling object, released from rest, requires 1.95 s to travel the last 23.5 m before it hits the ground. (a) Fi

Ratling [72]

Answer:

(a). The velocity of the object is -2.496 m/s.

(b). The total distance of the object travels during the fall is 23.80 m.

Explanation:

Given that,

Time = 1.95 s

Distance = 23.5 m

(a). We need to calculate the velocity

Using equation of motion

$s = ut+\dfrac{1}{2}gt^2$

Put the value into the formula

$-23.5=u\times1.95+\dfrac{1}{2}\times(-9.8)\times(1.95)^2$

$u=\dfrac{-23.5+4.9\times(1.95)^2}{1.95}$

$u=-2.496\ m/s$

(b). We need to calculate the total distance the object travels during the fall

Using equation of motion

$v = u+gt$

Put the value in the equation

$-2.496=0-9.8\times t$

$t =\dfrac{2.496}{9.8}$

$t=0.254\ sec$

The total time is

$t'=t+1.95$

$t'=0.254+1.95$

$t'=2.204\ sec$

We need to calculate the distance

Using equation of motion

$s = ut+\dfrac{1}{2}gt^2$

Put the value into the formula

$s=0+\dfrac{1}{2}\times9.8\times(2.204)^2$

$s=23.80\ m$

Hence, (a). The velocity of the object is -2.496 m/s.

(b). The total distance of the object travels during the fall is 23.80 m.

4 0

3 years ago

HELP ME PLS

crimeas [40]

Answer

-The magnitude of acceleration during the fall is greater

3 0

3 years ago

A __________ is a push or pull.

maria [59]

Answer:

force

Explanation:

Force is a push or a pull of an object that causes the object to speed up, slow down, or stay in one place. In other words, a force is what causes an object to move. Friction and gravity are two types of forces that influence how an object moves.

5 0

2 years ago