Answer:
0.53 m
Explanation:
First of all, we have to consider the vertical motion of the ball, in order to find the time it takes for the marble to reach the ground. The initial height is
, the initial vertical velocity is zero, while the acceleration is
, so the vertical position at time t is given by
![y(t)=h-\frac{1}{2}gt^2](https://tex.z-dn.net/?f=y%28t%29%3Dh-%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
By demanding y(t)=0, we find the time t at which the ball reaches the ground:
![0=h-\frac{1}{2}gt^2](https://tex.z-dn.net/?f=0%3Dh-%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
![t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(0.9 m)}{9.81 m/s^2}}=0.43 s](https://tex.z-dn.net/?f=t%3D%5Csqrt%7B%5Cfrac%7B2h%7D%7Bg%7D%7D%3D%5Csqrt%7B%5Cfrac%7B2%280.9%20m%29%7D%7B9.81%20m%2Fs%5E2%7D%7D%3D0.43%20s)
Now we can find the horizontal range of the marble: we know the initial horizontal speed (v=1.24 m/s), we know the total time of the motion (t=0.43 s), and since the horizontal speed is constant, the total distance traveled on the horizontal direction is
![x=vt=(1.24 m/s)(0.43 s)=0.53 m](https://tex.z-dn.net/?f=x%3Dvt%3D%281.24%20m%2Fs%29%280.43%20s%29%3D0.53%20m)
Answer:
Well, newer telephone circuits built during the last decade are based on the digital transmission, not on the analog transmission. So it's the digital transmission circuit that has made the higher quality. Digital circuits converts the voice signals into the binary codes which is then translated again into the voice signal at the receiving end.
The answer is false.
Explanation:
<u>Answer:</u> The Young's modulus for the wire is ![6.378\times 10^{10}N/m^2](https://tex.z-dn.net/?f=6.378%5Ctimes%2010%5E%7B10%7DN%2Fm%5E2)
<u>Explanation:</u>
Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.
The equation representing Young's Modulus is:
![Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}](https://tex.z-dn.net/?f=Y%3D%5Cfrac%7BF%2FA%7D%7B%5CDelta%20l%2Fl%7D%3D%5Cfrac%7BFl%7D%7BA%5CDelta%20l%7D)
where,
Y = Young's Modulus
F = force exerted by the weight = ![m\times g](https://tex.z-dn.net/?f=m%5Ctimes%20g)
m = mass of the ball = 10 kg
g = acceleration due to gravity = ![9.81m/s^2](https://tex.z-dn.net/?f=9.81m%2Fs%5E2)
l = length of wire = 2.6 m
A = area of cross section = ![\pi r^2](https://tex.z-dn.net/?f=%5Cpi%20r%5E2)
r = radius of the wire =
(Conversion factor: 1 m = 1000 mm)
= change in length = 1.99 mm = ![1.99\times 10^{-3}m](https://tex.z-dn.net/?f=1.99%5Ctimes%2010%5E%7B-3%7Dm)
Putting values in above equation, we get:
![Y=\frac{10\times 9.81\times 2.6}{(3.14\times (8\times 10^{-4})^2)\times 1.99\times 10^{-3}}\\\\Y=6.378\times 10^{10}N/m^2](https://tex.z-dn.net/?f=Y%3D%5Cfrac%7B10%5Ctimes%209.81%5Ctimes%202.6%7D%7B%283.14%5Ctimes%20%288%5Ctimes%2010%5E%7B-4%7D%29%5E2%29%5Ctimes%201.99%5Ctimes%2010%5E%7B-3%7D%7D%5C%5C%5C%5CY%3D6.378%5Ctimes%2010%5E%7B10%7DN%2Fm%5E2)
Hence, the Young's modulus for the wire is ![6.378\times 10^{10}N/m^2](https://tex.z-dn.net/?f=6.378%5Ctimes%2010%5E%7B10%7DN%2Fm%5E2)
Answer:
conductor
Explanation:
A "conductor" is a material that allows the charges to pass freely from one body to the other. This causes a movement among the electrons and this means that<em> the charge will be passed entirely to the object receiving it.</em> This is also called <em>"conductive material."</em>
Examples of conductors are: <em>copper, aluminum, gold, silver, seawater, etc.</em>
The opposite of conductors are called "insulators." These do not allow the free movement of charges from one object to the other.
Examples of insulators: <em>plastic, rubber, paper, glass, wool, dry air, etc.</em>