Answer:
The centripetal acceleration of the runner is 
.
Explanation:
Given that,
A runner completes the 200 m dash in 24.0 s and runs at constant speed throughout the race. We need to find the centripetal acceleration as he runs the curved portion of the track. We know that the centripetal acceleration is given by :
v is the velocity of runner
Centripetal acceleration,
So, the centripetal acceleration of the runner is . Hence, this is the required solution.
Answer:
c. 337
Explanation:
can someone answer my question
Hi there!
This is an example of a recoil collision.
Using the conservation of momentum:
The initial momentum is 0 kgm/s (objects start from rest), so:
We are given that the 15 kg block has a velocity of 12 m/s to the left, so:
Solve for v2':
0.33 . Equation is Force of friction equals normal force times coefficient of friction, so 6=18u. Divide 6 by 18
Kinetic energy=0.5*mass*(velocity^2)
15,000 J=0.5*50*v^2
15,000J=25v^2
600 J=v^2
Velocity= 24.49 ms^-1
