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BabaBlast [244]
3 years ago
9

Simplify completely (6x² - 54x + 84 / 8x² -40 x +48) ÷ (x² + x - 56 / 2x² + 12x -32)

Mathematics
1 answer:
VladimirAG [237]3 years ago
4 0

Answer:

The answer to your question is     \frac{3(x - 2)}{2(x - 3)} or \frac{3x - 6}{2x - 6}

Step-by-step explanation:

Expression \frac{6x^{2}- 54x + 84}{8x^{2} - 40x + 48} /  \frac{ x^{2} + x - 56}{2x^{2} + 12x - 32}

Process

1.- Change the division to a multiplication

                   \frac{6x^{2}- 54x + 84}{8x^{2} - 40x + 48} x \frac{2x^{2}+ 12x - 32}{x^{2} + x - 56}

2.- Factor

                   \frac{6(x^{2}- 9x - 14)}{8(x^{2} - 5x + 6)} x \frac{2(x^{2}+ 6x - 16)}{(x^{2} + x -56)}

                   \frac{6(x + 8)(x - 2)}{8(x - 3)(x - 2)} x \frac{2(x + 8)(x - 2)}{(x + 8)(x - 7)}

3.- Simplify (cancel the terms that are repeated in both numerator and denominator)

                  \frac{2(6)(x - 2)}{8(x - 3)}

                  \frac{3(x - 2)}{2(x - 3)} or \frac{3x - 6}{2x - 6}

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