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Burka [1]
3 years ago
15

what would happen if measurements such as mass,length,volume,or temperature weren't standardized and everyone made up their own

units
Physics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

The world would have been blown up by now.

Explanation:

Hypothetically, lets say that someone gave Kim Jong boi a cup of coffee.

He gets mad at the "public servant" since it didn't contain 3 posafa43asdunds of sugar which makes him "big".

The public servant claims they added jfoaj4su38093 units of sugar, which is equivalent to 3 posafa43asdunds.

He gets mad and launches big cannons at Trump since he blames Boe Jiden.

You might be interested in
A car travels a distance of 100 km in 2 hours. what is the average speed of the car (km/h)?
Naya [18.7K]

Answer:

50 km/h

Explanation:

Speed= distance\ hour

6 0
3 years ago
Read 2 more answers
A student catches a can of soda dropped from some unknown height by Mr. Fineman. If
nikdorinn [45]

Answer:

v² = u² + 2gh

8.9² = 0² + 2(9.8)h

h = 4.0 m

v = at

t = 8.9/9.8

t = 0.91 s

3 0
2 years ago
Do anyone know this ?
Galina-37 [17]

Answer:

Distance is 100m, displacement is 0m

Explanation:

Distance is how much you travelled in total (100m)

Displacement is when you compare your final and initial positions.

It is usually Final position - Initial position.

Since you start and finish at the same point, it would be 0 - 0 = 0m

So the displacement is 0m.

7 0
3 years ago
Read 2 more answers
A particle has ~r(0) = (4 m) ˆ and ~v(0) = (2 m/s)ˆı. If its acceleration is constant and given by ~a = −(2 m/s 2 ) (ˆı +ˆ), a
Troyanec [42]

The particle has \vec r(0)=(4\,\mathrm m)\,\vec\imath and \vec v(0)=\left(2\frac{\rm m}{\rm s}\right)\,\vec\imath, and is undergoing a constant acceleration of \vec a=-\left(2\frac{\rm m}{\mathrm s^2}\right)(\vec\imath+\vec\jmath).

This means its position at time t is given by the vector function,

\vec r(t)=\vec r(0)+\vec v(0)t+\dfrac12\vec a t^2

\implies\vec r(t)=\left[4\,\mathrm m+\left(2\dfrac{\rm m}{\rm s}\right)t-\left(1\dfrac{\rm m}{\mathrm s^2}\right)t^2\right]\,\vec\imath-\left(1\dfrac{\rm m}{\mathrm s^2}\right)t^2\,\vec\jmath

The particle crosses the x-axis when the \vec\imath component is 0 for some time t>0, so we solve:

4+2t-t^2=0\implies t^2-2t+1=5

\implies(t-1)^2=5

\implies t-1=\pm\sqrt5

\implies t=1\pm\sqrt5

The negative square root introduces a negative solution that we throw out, leaving us with \boxed{t=1+\sqrt5} or about 3.24 seconds after it starts moving.

3 0
4 years ago
What net force is necessary to give a 2 kg mass that is initially at rest an acceleration of 5 m/s2?
QveST [7]

Answer:

<h2>10 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 2 × 5

We have the final answer as

<h3>10 N</h3>

Hope this helps you

7 0
3 years ago
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