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faust18 [17]
3 years ago
11

Find the greatest commonFoctor for these numbers 18, 42, 96​

Mathematics
1 answer:
ycow [4]3 years ago
5 0

Answer:

The greatest common factor for 18,42 and 96 is 6.

Step-by-step explanation:

6 X 3 = 18

6 X 7 = 42

6 X 16 = 96  

making 6 your largest common factor.

You might be interested in
A basket had 120 star apples and mangoes.if there are 90 mangoes what is the ratio of mangoes to star apples.?
leva [86]

Answer:

3 : 1

Step-by-step explanation:

120-90=30

90 mangoes

30 apples

90 : 30 divide both by 10

9 : 3 divide both by 3

3 : 1

6 0
3 years ago
3(x - 6) + 6 = 5x - 6. what is the solution<br>​
4vir4ik [10]

Answer:

x=-3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3(x−6)+6=5x−6

(3)(x)+(3)(−6)+6=5x+−6(Distribute)

3x+−18+6=5x+−6

(3x)+(−18+6)=5x−6(Combine Like Terms)

3x+−12=5x−6

3x−12=5x−6

Step 2: Subtract 5x from both sides.

3x−12−5x=5x−6−5x

−2x−12=−6

Step 3: Add 12 to both sides.

−2x−12+12=−6+12

−2x=6

Step 4: Divide both sides by -2.

−2x

−2

=

6

−2

x=−3

7 0
3 years ago
Read 2 more answers
Factored 6x2 – 31x - 30 ​
ELEN [110]

Answer:

942

Step-by-step explanation:

I used the clculater

3 0
3 years ago
The table gives estimates of the world population, in millions, from 1750 to 2000. year population year population 1750 790 1900
Tems11 [23]
The poopulation exponential model is given by

P(t)=P_0e^{kt}

Where, P(t) is the population after year t; Po is the initial population, t is the number of years from the starting year; k is the groth constant.

Given that the population in 1750 is 790 and the population in 1800 is 970, we obtain the population exponential equation as follows:

970=790e^{50k} \\  \\ \Rightarrow e^{50k}=1.228 \\  \\ \Rightarrow 50k=\ln{1.228}=0.2053 \\  \\ \Rightarrow k=0.0041

Thus, the exponential equation using the 1750 and the 1800 population values is P(t)=790e^{0.0041t}

The population of 1900 using the 1750 and the 1800 population values is given by

P(t)=790e^{0.041\times150} \\  \\ =790e^{0.6158}=790(1.8511) \\  \\ =1,462

The population of 1950 using the 1750 and the 1800 population values is given by

P(t)=790e^{0.041\times200} \\  \\ =790e^{0.821}=790(2.2729) \\  \\ =1,796

From the table, it can be seen that the actual figure is greater than the exponential model values.
7 0
3 years ago
Answer please<br>Mathematics​
Vilka [71]
<h3>Answers:</h3>
  1. b) 573
  2. b) 0
  3. b) 3308
  4. a) 0
  5. a) 20

<h3>Hope it helps..</h3>

ray4918 here to help..

8 0
2 years ago
Read 2 more answers
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