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ANTONII [103]
3 years ago
13

Female human reproduction explaination

Biology
2 answers:
Archy [21]3 years ago
6 0
Female human reproduction answer:

Alenkasestr [34]3 years ago
3 0

Answer:

Female human reproduction is the way how female humans produce.

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A person with a genotype of HbSS has sickle cell disease. A person with a genotype of HbAS allele carries the sickle cell trait.
Mariana [72]

Answer:

There is a 25% chance that the offspring will have sickle cell anemia (SS)

Explanation:

Sickle cell anemia is a genetic disease, where red blood cells can take the shape of a crescent (sickle), and this change allows the red blood cells to be more easily destroyed, causing anemia.  Sickle cell anemia is caused by defective hemoglobin (Hb), which is the oxygen carrying protein in blood cells.  Hemoglobin is made up of four peptide chains, each bound to a heme group.  Different hemoglobins have different combinations of these chains.  Hemoglobin A (HbA) is the primary hemoglobin affected in sickle cell, because their beta-globin chains end up misshapen because of a genetic mutation in the beta-globin gene.  Sickle cell anemia is an autosomal recessive disease, so there needs to be a mutation in both copies of the beta-globin gene in order to get the disease.  If a person has just one copy of the mutated gene and the other copy is normal for the gene, then they are a sickle cell carrier.

So first of all, this looks like a dihybrid cross, but it is not because we are dealing with one pair of alleles (gene that causes sickle cell), so we will actually be doing a monohybrid cross.

So let’s go through the alleles step by step:

Hb = hemoglobin (constant, all red blood cells have hemoglobin, we are looking at the mutation in the beta globin gene of the hemoglobin which will be the allele we focus on)

SS = sickle cell (mutated beta globin gene (S) x 2)

AA = normal beta globin gene (A) x 2 (no sickle cell)

AS = carrier (one sickle cell gene + one normal gene)

HbAS x HbAS

Carrier x carrier

PARENTS A S

   A               AA AS

  S               AS SS

25% chance that the offspring will have a normal (does not have sickle cell anemia) genotype (AA)

50 % chance that the offspring will be carriers (AS)

25% chance that the offspring will have sickle cell anemia (SS)

4 0
3 years ago
Read 2 more answers
Similarities between dna and rna
bonufazy [111]
Both have phosphate-pentose back bone, as well as both have adenine, cytosine and guanine bases. 
5 0
3 years ago
Differenciate between mixed cropping and mixed farming.<br> ​
hammer [34]

Answer:

Mixed cropping- Mixed cropping, including intercropping, is the oldest form of systemized agricultural production and involves the growing of two or more species or cultivars of the same species simultaneously in the same field. ... The majority of cropping systems in this region are usually monocultures, except for forage grass mixtures.

Mixed farming- Mixed farming is a type of farming which involves both the growing of crops and the raising of livestock. ... For example, a mixed farm may grow cereal crops such as wheat or rye and also keep cattle, sheep, pigs or poultry. Often the dung from the cattle serves to fertilize the cereal crops.

pls give brainliest for the answer

5 0
3 years ago
Read 2 more answers
The cheetah population was around 100,000 in 1900. Today, fewer than 12,000 cheetahs remain. What type of natural resource are c
sasho [114]

Non-renewable resource

Explanation:

The cheetahs can be considered a non-renewable resource. Non-renewable implies that a resource cannot be replenished at it current rate of depletion.

How much has the cheetah's population declined:

         percentage declination = \frac{Population in 1990}{Population today} x 100

Population in 1990 = 100,000

Population today = 12,000

  Percentage declination = \frac{100000}{12000} x 100 = 83.3%

We can see that the cheetah has suffered a whooping 83.3% decline in their population.

A renewable resource is one that can be replenished as it is being used such as water, air, e.t.c.

Learn more:

Renewable resources brainly.com/question/6944540

#learnwithBrainly

8 0
3 years ago
In a mating between two individuals that are heterozygous for a recessive lethal allele that is expressed in utero, what genotyp
Nuetrik [128]

Answer:

1:2:0

Explanation:

If two recessive lethal alleles come together, they will be expressed and lead to the offspring's death. Let the dominant allele be S and the recessive allele be s. Here, the two individuals are heterozygous for it. So when they mate:

    S     s

S  SS  Ss

s   Ss   ss

1/4 have homozygous fominant genotype (SS), 2/4 have heterozygous genotype (Ss) and 1/4 have homozygous recessive (ss) genotype. Since 1/4 offspring have ss genotype, they will die. Hence, the usual 1:2:1 ratio has been modified here to only 1:2:0

3 0
4 years ago
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