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2 years ago

A reaction happens quickest during:

Chemistry

2 answers:

Naya [18.7K]2 years ago

7 0

Answer:

According to me the answer of the question is option A

If you like my answer than please mark me brainliest thanks

balandron [24]2 years ago

3 0

The answer is A
Explanation;
At the start of the reaction, when we first put magnesium in the hydrochloric acid, there is 100% of the magnesium to react with. As a result there will be more successful collisions between the reactant particles. The more successful collisions, the faster the reaction will be.

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Which part of the mantle is still a solid but flows like a thick, heavy liquid?

marusya05 [52]

Hello!

Your answer is A, asthenosphere

The asthenosphere is a part of the mantle. It helps move the plates in the Earth.

It is below the lithosphere, between 80 and 200 km below the surface.

Therfore, the asthenosphere is the part of the mantle that is still a solid but flows like a thick, heavy liquid.

Hope this helps!

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3 years ago

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jok3333 [9.3K]

Answer:

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2 years ago

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Vera_Pavlovna [14]

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3 years ago

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Roman55 [17]

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3 years ago

how many kilograms of a 35% m/m sodium chlorate solution is needed to react completely with 0.29 l of a 22% m/v aluminum nitrate

Stolb23 [73]

Answer:- 0.273 kg

Solution:- A double replacement reaction takes place. The balanced equation is:

$3NaClO_3+Al(NO_3)_3\rightarrow 3NaNO_3+Al(ClO_3)_3$

We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.

$0.29L(\frac{1000mL}{1L})(\frac{22g}{100mL})$

= 63.8 g aluminum nitrate

From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.

We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.

$63.8gAl(NO_3)_3(\frac{1mol}{212.99g})(\frac{3molNaClO_3}{1molAl(NO_3)_3})(\frac{106.44g}{1mol})$

= $95.7gNaClO_3$

sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate and then the grams are converted to kg.

$95.7gNaClO_3(\frac{100gSolution}{35gNaClO_3})(\frac{1kg}{1000g})$

= 0.273 kg

So, 0.273 kg of 35% m/m sodium chlorate solution are required.

7 0

3 years ago