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ratelena [41]
3 years ago
11

How many moles of H2SO4 are needed to completely react with 15.0 mole of Al?

Chemistry
1 answer:
mezya [45]3 years ago
8 0

Answer:

The answer to your question is 22.5 moles of H₂SO₄

Explanation:

Data

moles of H₂SO₄ = ?

moles of Al = 15

Balanced chemical reaction

                2Al + 3H₂SO₄  ⇒  Al₂(SO₄)₃  +  3H₂

To solve this problem use proportions and cross multiplication. Use the coefficients of the balanced chemical reaction.

                2 moles of Al ------------------- 3 moles of H₂SO₄

               15 moles of Al ------------------  x

                                    x = (15 x 3) / 2

                                    x = 45/2

                                   x = 22.5 moles of H₂SO₄

-Conclusion

22.5 moles of H₂SO₄ react completely with 15 moles of Al.

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Explanation:

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Menstruation occurs on a ______ interval from puberty until menopause
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Which substance would have the highest melting point, based on electronegativity?
Mazyrski [523]

Answer:

H₂O

Explanation:

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5 0
3 years ago
If 40.0 mL of a calcium nitrate solution reacts with excess potassium carbonate to yield 0.524 grams of a precipitate, what is t
tankabanditka [31]

Answer : The molarity of calcium ion on the original solution is, 0.131 M

Explanation :

The balanced chemical reaction is:

Ca(NO_3)_2+K_2CO_3\rightarrow CaCO_3+3KNO_3

When calcium nitrate react with potassium carbonate to give calcium carbonate as a precipitate and potassium nitrate.

First we have to calculate the moles of CaCO_3

\text{Moles of }CaCO_3=\frac{\text{Mass of }CaCO_3}{\text{Molar mass of }CaCO_3}

Given:

Mass of CaCO_3 = 0.524 g

Molar mass of CaCO_3 = 100 g/mol

\text{Moles of }CaCO_3=\frac{0.524}{100g/mol}=0.00524mol

Now we have to calculate the concentration of CaCO_3

\text{Concentration of }CaCO_3=\frac{\text{Moles of }CaCO_3}{\text{Volume of solution}}=\frac{0.00524mol}{0.040L}=0.131M

Now we have to calculate the concentration of calcium ion.

As, calcium carbonate dissociate to give calcium ion and carbonate ion.

CaCO_3\rightarrow Ca^{2+}+CO_3^{2-}

So,

Concentration of calcium ion = Concentration of CaCO_3 = 0.131 M

Thus, the concentration or molarity of calcium ion on the original solution is, 0.131 M

4 0
3 years ago
*PLEASE HELP ASAP*
dimulka [17.4K]
I believe its true , because when two elements form different compounds a given mass of one element will combine with the other , during any chemical change atoms arent created or destroyed they are jus rearranged
5 0
3 years ago
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